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tatiyna
3 years ago
12

How much Sr(OH)2 • 8 H2O (M = 265.76) is needed to

Chemistry
1 answer:
Degger [83]3 years ago
3 0
First, you need to find the number of moles of OH⁻ in a 250mL solution of 0.100M OH⁻.  To do this, multiply 0.250L by 0.100M to get 0.025mol OH⁻.  Then you use the fact that 1 mole of Sr(OH₂)·8H₂O contains 2 moles of OH⁻ which means that 0.0125mol of Sr(OH)₂·8H₂O contains 0.025mol OH⁻ (0.025/2=0.0125).  Then to find the amount of Sr(OH)₂·8H₂O is needed you multiply its molar mass (265.76g/mol) by 0.0125mol to get 3.322g.
Therefore you need 3.322g of Sr(OH)₂·8H₂O.

I hope that helps.  Let me know if anything is unclear.
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How many molecules of H2O and O2 is present in 8.5g of H2O?​
Igoryamba

Answer:

2.8 x 10²³ molecules H₂O

1.4 x 10²³ molecules O₂

Explanation:

First, you will need the balanced chemical equation for the formation of water:

2H₂ + O₂ -> 2H₂O

This will help in determining the mole ratios between water and oxygen, which we will need later.

Let's first calculate the number of H₂O (water) molecules. This will require stoichiometry. We are also given the mass, so we must convert mass into moles, then moles into molecules. mass -> moles -> molecules

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (6.02 x 10²³ molecules H₂O/1 mol H₂O) = 2.8404 x 10²³ molecules H₂O

Rounded to 2 significant digits: 2.8 x 10²³ molecules H₂O

Now, to find the molecules of water, we can begin with the same stoichiometric equation, but before we convert to molecules, we will have to convert moles of water to moles of oxygen. This is where we will use the mole ratio of water to oxygen we got from the balanced chemical equation earlier. 2H₂O:1O₂

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (1 mol O₂/2 mol H₂O) x (6.02 x 10²³ molecules O₂/1 mol O₂) = 1.4202 x 10²³ molecules O₂

Rounded to 2 significant digits: 1.4 x 10²³ molecules O₂

3 0
3 years ago
An aqueous solution of perchloric acid is standardized by titration with a 0.191 M solution of barium hydroxide. If 13.8 mL of b
WARRIOR [948]

Answer:

Molarity of HClO_{4} solution is 0.311 M

Explanation:

Neutralization reaction: 2HClO_{4}+Ba(OH)_{2}\rightarrow Ba(ClO_{4})_{2}+2H_{2}O

According to balanced reaction, 1 mol of Ba(OH)_{2} neutralizes 2 moles of HClO_{4}

Number of moles of Ba(OH)_{2} in 13.8 mL of 0.191 M Ba(OH)_{2} solution = \frac{0.191}{1000}\times 13.8moles = 0.00264moles

Let's assume molarity of HClO_{4} solution is C (M) then-

Number of moles of HClO_{4} in 17.0 mL of C (M) HClO_{4} solution = \frac{C}{1000}\times 17.0moles = 0.017Cmoles

Hence, 0.017C=(2\times 0.00264)

         or, C=0.311

So, molarity of HClO_{4} solution is 0.311 M

3 0
3 years ago
How do you convert from Fahrenheit to Celsius temperatures
scoray [572]
You take the temperature and follow these steps:

Take the temperature in farenheit, suntract 32, then multiply that by 5, and divide by 9.
8 0
3 years ago
Read 2 more answers
To convert from liters/second to cubic gallons/minute, multiply the number of liters/second by 15.850 0 0.0353 00.2642 0 60
ivanzaharov [21]

Answer: 15.850

Explanation:

The conversion used from liters to gallons is:

1 L = 0.264172 gallon

The conversion used from sec to min is:

60 sec = 1 min

1 sec =\frac{1}{60}\times 1=0.017min

We are asked: liters/sec = gallons/min

liters/sec=\frac{0.264172}{0.017}=15.850gallons/min

Therefore, to convert from liters/second to gallons/minute, multiply the number of liters/second by 15.850.

8 0
4 years ago
Aluminum, silicon, and oxygen form minerals known as aluminosilicates. How many moles of aluminum are in 0.900 moles of pyrophyl
wlad13 [49]

Answer:

There are 1.8 moles of aluminum.

Explanation:

To solve this problem we need to convert moles of pyrophillite (Al₂Si₄O₁₀(OH)) into moles of aluminum (Al):

  • In one mol of Al₂Si₄O₁₀(OH) there are two moles of Al.

With the above information in mind we can now <u>do the conversion</u>:

  • 0.900 moles Al₂Si₄O₁₀(OH) * \frac{2molAl}{1molAl_2Si_4O_{10}(OH)}= 1.8 mol Al

Thus the answer is that there are 1.8 moles of aluminum.

3 0
4 years ago
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