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2 years ago

How much Sr(OH)2 • 8 H2O (M = 265.76) is needed to

1 answer:

3 0

First, you need to find the number of moles of OH⁻ in a 250mL solution of 0.100M OH⁻. To do this, multiply 0.250L by 0.100M to get 0.025mol OH⁻. Then you use the fact that 1 mole of Sr(OH₂)·8H₂O contains 2 moles of OH⁻ which means that 0.0125mol of Sr(OH)₂·8H₂O contains 0.025mol OH⁻ (0.025/2=0.0125). Then to find the amount of Sr(OH)₂·8H₂O is needed you multiply its molar mass (265.76g/mol) by 0.0125mol to get 3.322g.
Therefore you need 3.322g of Sr(OH)₂·8H₂O.

I hope that helps. Let me know if anything is unclear.

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What is one energy transformation that is taking place in the photo?

Galina-37 [17]

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2 years ago

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If the density of mercury is 13.6g/ml, how many ml of mercury are in 1,000 g of mercury?

Illusion [34]

Answer:

Explanation:

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$volume = \frac{mass}{density} \\$

From the question we have

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2 years ago

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Lyrx [107]

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PLEASE HURRY AND SHOW WORK

IgorC [24]

Answer:

The answer to your question is P = 1.64 atm

Explanation:

Data

Volume = 2.5 x 10⁷ L

Temperature = 22°C

Pressure = ?

Moles = 1.7 x 10⁶

R = 0.082 atm L/ mol°K

Process

1.- Convert temperature to °K

Temperature = 22 + 273

= 295°K

2.- Use the Ideal gas law to solve this problem

PV = nRT

- Solve for P

P = nRT / V

- Substitution

P = (1.7 x 10⁶)(0.082)(295) / 2.5 x 10⁷

- Simplification

P = 41123000 / 2.5 x 10⁷

- Result

P = 1.64 atm

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2 years ago

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Vesna [10]

Answer:

See explanation

Explanation:

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2 years ago