Answer:
Protonated form: 96.87%
Unprotonated form: 3.13%
Explanation:
To find the percentage of protoned and unprotoned forms of salicylic acid we must use Henderson-Hasselbalch equation:
pH = pKa + log [A⁻] / [HA]
<em>Where pKa of salicylic acid is 3.49; [A⁻] is the unprotonated form and [HA]:</em>
<em />
2.0 = 3.49 + log [A⁻] / [HA]
0.03236 = [A⁻] / [HA] <em>(1)</em>
And as:
[A⁻] + [HA] = 100% <em>(2)</em>
<em></em>
Replacing (2) in (1):
0.03236 = 100 - [HA] / [HA]
0.03236 [HA] = 100 - [HA]
1.03236[HA] = 100
<h3>[HA] = 96.87%</h3>
And [A⁻]:
[A⁻] = 100 - 96.87
<h3>[A⁻] = 3.13%</h3>
<em></em>
Answer:
9.62 × 10² J
Explanation:
In this problem, we need to convert 230 calories to joules. For this, we must know the conversion from calories to joules.
1 Calorie = 4.184 Joules
To find Joules in 230 calories, multiply 4.184 by 23. So,
230 Calorie = (230 × 4.184) Joules
= 962.32 Joules
or
230 Calories = 9.62 × 10² J
So, the correct option is (A).
Answer:
Chlorine gas is the limiting reactant
11.57 g
Explanation:
The equation of the reaction is;
2Al(s) + 3Cl2(g) -----> 2AlCl3(s)
The limiting reactant will produce the least number of moles of AlCl3.
For Al
Number of moles reacted = 2.43 g/27 g/mol = 0.09 moles
2 moles of Al yields 2 moles of AlCl3
0.09 moles of Al yields 0.09 * 2/2 = 0.09 moles of AlCl3
For Cl2
9.22g/71g/mol = 0.13 moles
3 moles of Cl2 yields 2 moles of AlCl3
0.13 moles of Cl2 yields 0.13 * 2/3 = 0.087 moles of AlCl3
Hence Cl2 is the limiting reactant
b) Mass of product produced = 0.087 moles of AlCl3 * 133g/mol = 11.57 g
The temperature of the 1 kg water will be lower.
Q=mcΔt
Q1= 1kg*c*Δt(1)
Q2= 2kg*c*Δt(2)
Q1=Q2
1kg*c*Δt(1) = 2kg*c*Δt(2)
Δt(1) = 2Δt(2)
We can see that change in temperature for 1 kg will be 2 times more that change in temperature for 2 kg of water.
Answer:
FLUORINE, CHLORINE, BROMINE, IODINE, ASTATILE AND TENNESINE
Explanation :
Florine and chorine=gas
Bromine=liquid
ASTATILE and TENNESINE =solid
HOPE IT is right
