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3 years ago

Ca(s)+2hno3(aq)→ca(no3)2(aq)+h2(g) identify the oxidizing agent.

Chemistry

2 answers:

aleksandr82 [10.1K]3 years ago

8 0

To find for the oxidizing agent, first let us write the half reactions of this complete chemical reaction:

Ca = Ca2+ + 2e- <span>
2 H+ + 2e- = H2</span>

The oxidizing agent would be the substance of the element that is reduced. We know that an element is reduced when an electron is added to it. In this case, the element being reduced is H. Therefore the oxidizing agent is HNO3.

Answer:

Nuetrik [128]3 years ago

8 0

Answer:

Nitric acid is an oxidizing agent in the given reaction.

Explanation:

Oxidizing agents : Agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents : Agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

In the given reaction;

$Ca(s)+2HNO_3(aq)\rightarrow Ca(NO_3)_2(aq)+H_2(g)$

Oxidizing agent in the above reaction is a nitric acid which oxidizes calcium metal into calcium ion $Ca^{2+}$

$Ca\rightarrow Ca^{2+}+2e^-$

Here calcium atom is undergoing oxidation reaction which is the reaction in which an atom looses its electrons and its oxidation state increases.

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Answer:Explanation:

In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species.

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3 years ago

How many moles are 21.67 L of NH4CI?

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Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl = 21.67L

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Number of moles = ?

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3 years ago

Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,

8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

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Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

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(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

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3 years ago

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Explanation:

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Bromine is a highly electronegative non-metal which is a halogen.
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3 years ago

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