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Lina20 [59]
3 years ago
10

Ca(s)+2hno3(aq)→ca(no3)2(aq)+h2(g) identify the oxidizing agent.

Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

To find for the oxidizing agent, first let us write the half reactions of this complete chemical reaction:

Ca = Ca2+ + 2e- <span>
2 H+ + 2e- = H2</span>

 

The oxidizing agent would be the substance of the element that is reduced. We know that an element is reduced when an electron is added to it. In this case, the element being reduced is H. Therefore the oxidizing agent is HNO3.

 

Answer:

<span>HNO3</span>

Nuetrik [128]3 years ago
8 0

Answer:

Nitric acid is an oxidizing agent in the given reaction.

Explanation:

Oxidizing agents : Agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents : Agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

In the given reaction;

Ca(s)+2HNO_3(aq)\rightarrow Ca(NO_3)_2(aq)+H_2(g)

Oxidizing agent in the above reaction is a nitric acid which oxidizes calcium metal into calcium ionCa^{2+}

Ca\rightarrow Ca^{2+}+2e^-

Here calcium atom is undergoing oxidation reaction which is the reaction in which an atom looses its electrons and its oxidation state increases.

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ure carbon tetrachloride, CCl4, freezes at-23.00 ⁰C and has a kf of 29.8⁰C/m. The latest lot has a freezing point of-23.43⁰C. Wh
lesya692 [45]

Answer:

a) grams of this impurity per kg of CCl4 = 3.416 g/kg of solvent.

b) mass purity % = 99.66%

Explanation:

Given, the freezing point of pure CCl₄ = - 23°C

Presence of impurities lowers the freezing point to - 23.43°C

The freezing point depression constant, Kբ = 29.8°C/m

The lowered freezing point is related to all the parameters through the relation

ΔT = i Kբ × m

where ΔT is the lowered freezing point, that is, the difference between freezing point of pure substance (T⁰) and freezing point of substance with impurities (T).

i = Van't Hoff factor which measures how much the impurities influence/affect colligative properties (such as freezing point depression) and for most non-electrolytes like this one, it is = 1

Kբ = The freezing point depression constant = 29.8°C/m

m = Molality = ?

T⁰ - T = i Kբ m

- 23 - (-23.43) = 1 × 29.8 × m

m = 0.43/29.8 = 0.0144 mol/kg

Them we're told to calculate impurity of the CCl₄

we convert the Molality to (gram of solute)/(kg of solvent) first

Solute = C₂Cl₆

Molar mass = 236.74 g/mol

So, (molality × molar mass) = (gram of solute)/(kg of solvent)

(gram of solute)/(kg of solvent) = 0.0144 × 236.74 = 3.416 (gram of solute)/(kg of solvent)

Mass purity % = (1000 g of pure substance)/(1000 g of pure substance + mass of impurity in 1000 g of pure substance)

1000 g of solvent contains 3.416 grams of impurities

Mass purity % =100% × 1000/(1003.416)

Mass purity % = 99.66 %

3 0
4 years ago
3. Meteorologists refer to the water vapor in the atmosphere as
Oduvanchick [21]
A. Humidity

I hope this helped!
8 0
3 years ago
Read 2 more answers
Most immigrants from the 1820 to 1850 came from which two countries? France and the United Kingdom Ireland and Germany Ireland a
Vera_Pavlovna [14]
Ireland and germany!!
5 0
3 years ago
Read 2 more answers
An alternative definition of electronegativity is: Electronegativity = constant (I.E. – E.A.)where I.E. is the ionization energy
kolbaska11 [484]

The missing data is the value of I.E and E.A for Cl and F, which are, Cl: I.E =1255 kJ/mol, E.A = -348.7 kJ/mol, F: I.E = 1678 kJ/mol, E.A = -327.8 kJ/mol.

Answer:

3.2

Explanation:

The electronegativity is the capacity of an atom to attract an electron in a bond. As higher is it, as higher the electron will be attracted. The ionization energy is the minimum energy necessary to remove one electron of the atom, transforming it on a cation. On the other hand, the electron affinity is the energy that is lost when the atom gains an electron and is transformed on an anion.

Calling the constant as K, and knowing that the electronegative of fluorine (F) is 4.0:

4 = K*(1678 - (-327.8))

2005.8K = 4

K = 2.00x10⁻³ mol/kJ

Thus, for chlorine (Cl):

Electronegativity = 2.00x10⁻³*(1255 - (-348.7))

Electronegativity = 3.2

4 0
3 years ago
What physical properties can be used to separate heterogeneous mixture's?
marysya [2.9K]
Evaporation, distillation, filtration and chromatography
Hope it help you, have a nice day
7 0
3 years ago
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