Ask question

Ask question

All categories

3 years ago

8

Draw the lewis formula for chlorobenzene, a benzene derivative. include all hydrogen atoms and lone pairs.

1 answer:

larisa86 [58]3 years ago

4 0

<span>Chlorobenzene is an aromatic organic compound with the chemical formula C6H5CI. This of benzene in the presence of a catalytic amount Lewis acid such as ferric chloride, sulfur dichloride, and anhydrous aluminum chloride. Upon entering the body, typically via contaminated air, chlorobenzene is excreted both via the lungs and the urinary system.</span>

You might be interested in

What is the coefficient in front of the O₂ when the equation below is balanced C₂H₆O₂(g) + O₂ (g) → CO₂(g) + H₂O (g)

Maslowich

Answer:

5

Explanation:

Balance the equation in order of C,H,O and then you should be able to find the coefficient

5 0

2 years ago

A parachute on a racing dragster opens and changes the speed of the car from 85 m/s to 45 m/s in a period of 4.5 seconds. What i

LiRa [457]

Answer:

- 8.89 $m/s^{2}$

Explanation:

$\frac{(Vf-Vo)}{time}$ = $\frac{(45-85 m/s)}{4.5s}$ = - 8.89 $m/s^{2}$

7 0

3 years ago

Read 2 more answers

When ethyl-2-methylpropanoate is treated with sodium ethoxide in ethanol, there is no observable reaction. Explain this observat

den301095 [7]

Answer:

No net change in reaction occurs in this nucleophilic acyl subtitution reaction

Explanation:

Sodium ethoxide in ethanol gives nucleophilic acyl substitution reaction with ethyl-2-methylpropanoate.

Here ethoxide group replaces an ethoxide group from ester through addition-ellimination pathway.

So, ultimately, the product of this reaction is identical with reactant i.e. ethyl-2-methylpropanoate is reproduced.

Hence one might observe no change during reaction as product and reactant of this reaction are same.

Mechanistic pathway has been shown below.

8 0

3 years ago

2 icl + h2i2 + 2 hcl is first order in icl and second order in h2. Complete the rate law for this reaction in the box below. Use

OleMash [197]

2 ICl + H2 ----> I2 + 2 HCl

as given that rate is first order with respect to ICl and second order with respect to H2

The rate law will be

Rate = K [ICl] [ H2]^2

b) Given that K = 2.01 M^-2 s^-1

Concentrations are

[ICl] = 0.273 m and [H2] = 0.217 m

Therefore rate = 2.01 X (0.273)(0.217)^2 = 0.0258 M / s

5 0

2 years ago

The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true

Temka [501]

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

5 0

2 years ago