The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
- <em>mass of the bullet, = m₁</em>
- <em>mass of the block, = m₂</em>
- <em>initial velocity of the bullet, = u₁</em>
- <em>initial velocity of the block, = u₂</em>
Considering inelastic collision, the final velocity of the system is calculated as;

The time of motion of the system form top of the table is calculated as;

Considering elastic collision, the final velocity of the system is calculated as;

Apply one-directional velocity

Substitute the value of
into the above equation;

where;
is the final velocity of the block after collision
<em>Since the</em><em> bullet bounces off</em><em>, we assume that </em><em>only the block fell </em><em>to the ground from the table.</em>
The time of motion of the block is calculated as follows;

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

Learn more about elastic and inelastic collision here: brainly.com/question/7694106
Answer:
no 2 A graph with the x axis labelled X and Y axis labelled Y
Answer:
dart's speed is 11.77 m/s
Explanation:
given data
mass of the gun m = 355 gram = 0.355 kg
height = 18.3 centimeters = 0.183 m
dart = 57.0 gram = 0.057 kg
to find out
dart's speed
solution
we apply here law of conservation of energy that is express as
mgh = 0.5 × m × v² ...........1
so speed of gun will be here as
V =
..................2
V =
V = 1.89 m/s
and
now we find speed of dart by use law of conservation of momentum that is
M×V = m×v ...............3
so speed of the dart is
v = 
v = 
v = 11.77 m/s
so dart's speed is 11.77 m/s
Answer:
the first one answer is no