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DochEvi [55]
3 years ago
12

Russell drags his suitcase 15.0 M from the door of his house to the car at a constant speed with a horizontal force of 95.0 N. H

ow much work does Russell do to overcome the force of
Physics
1 answer:
igomit [66]3 years ago
5 0

The work done is 1425 J

Explanation:

The work done by a force to move an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and of the displacement

For the suitcase in this problem, we have:

F = 95.0 N is the force applied

d = 15.0 m is the displacement

\theta=0, since the force is parallel to the displacement

Substituting, we find

W=(95.0)(15.0)(cos 0)=1425 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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The fine horizontal scratches etched onto a bullet after it has been fired are called?
GalinKa [24]

The fine horizontal scratches etched onto a bullet after it has been fired are called Striations.

<h3>What is Striations?</h3>
  • Striations are the minute differences in the curve of the bullet's surface. The bullet and the gun barrel are the harder and softer materials, respectively, in firearms evidence.
  • The striations left on the fired bullet are used as a comparison by firearm examiners.
  • When a gun is discharged, the bullet blasts down the barrel where it strikes ridges and grooves, spinning and improving shot accuracy.
  • These ridges cause striations in the bullet's soft metal by digging into it.
  • An examiner analyses these distinctive markings to verify whether a given bullet was shot from a specific firearm.
  • A barrel will produce individual markings in addition to a bullet's land and groove impressions as the projectile passes through.

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4 0
2 years ago
The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
SpyIntel [72]

Answer:

Magnitude of the Frictional force = (mv₀²)/2x₁

Explanation:

For the frictional force to stop the box, it has to produce the deceleration of the box; thereby being the opposing force to the box's motion.

According to Newton's first law of motion

Frictional force = (mass of the box) × (deceleration experienced by the box)

Let the mass of the box be m

Then,

Frictional force = ma

Then we can obtain the deceleration using the equations of motion

v² = u² + 2ax

u = Initial velocity = v₀ m/s

v = Final velocity = 0 m/s (since the box comes to rest at the end)

x = horizontal distance covered = (x₁ - x₀) = x₁ (since x₀ = 0)

a = ?

v² = u² + 2ax

0 = (v₀)² + 2ax₁

2ax₁ = - v₀²

a = - (v₀²)/(2x₁) (minus sign, because it's a deceleration)

Magnitude of the Frictional force = ma = (mv₀²)/2x₁

4 0
3 years ago
1. Gwen exerts a 16 N horizontal force as she pulls a 32N sled across a cement
PSYCHO15rus [73]

Answer:

3.6 N   Kinetic friction

Explanation:

3 )   Ff = uk * Fn = 3.6 N

5 0
2 years ago
An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Papessa [141]

Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is \dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )

Now, using the pulse spread formula:

\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda

\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

Thus, the pulse spreading as a result of  material dispersion is:\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

3 0
3 years ago
Please help brainliest ASAP...........
pantera1 [17]

Answer:

I believe it is gender

Explanation:

8 0
3 years ago
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