1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Likurg_2 [28]
2 years ago
6

3. What is the acceleration of a car at rest that stays at rest over 10 seconds?

Physics
1 answer:
Yuliya22 [10]2 years ago
8 0

Answer:

a.

Explanation:

Use accleration formula,

a =  \frac{v _{f} - v _{i}}{t}

The initial velocity and final velocity is at zero. and t=10

So we got

\frac{0}{10}  = 0

so

a = 0

a is the answer

You might be interested in
A camper walks away from camp. He walks 23.72m north, then 39.25m south and
Arte-miy333 [17]

Answer:

89.53    North

Explanation:

Total N-S displacement

   23.72  -  39.25 + 105.06   =  + 89.53

5 0
2 years ago
A rocket travels in the x-direction at speed 0.70c with respect to the earth. An experimenter on the rocket observes a collision
marishachu [46]

Answer:

A) The space time coordinate x of the collision in Earth's reference frame is

x \approx 103,46x10^{9}m.

B) The space time coordinate t of the collision in Earth's reference frame is

t=377,29s

Explanation:

We are told a rocket travels in the x-direction at speed v=0,70 c (c=299792458 m/s is the exact value of the speed of light) with respect to the Earth. A collision between two comets is observed from the rocket and it is determined that the space time coordinates of the collision are (x',t') = (3.4 x 10¹⁰ m, 190 s).

An event indicates something that occurs at a given location in space and time, in this case the event is the collision between the two comets. We know the space time coordinates of the collision seen from the reference frame of the rocket and we want to find out the space time coordinates in Earth's reference frame.

<em>Lorentz transformation</em>

The Lorentz transformation relates things between two reference frames when one of them is moving with constant velocity with respect to the other. In this case the two reference frames are the Earth and the rocket that is moving with speed v=0,70 c in the x axis.

The Lorentz transformation is

                          x'=\frac{x-vt}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

                                y'=y

                                z'=z

                          t'=\frac{t-\frac{v}{c^{2}}x}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

prime coordinates are the ones from the rocket reference frame and unprimed variables are from the Earth's reference frame. Since we want position x and time t in the Earth's frame we need the inverse Lorentz transformation. This can be obtained by replacing v by -v and swapping primed an unprimed variables in the first set of equations

                       x=\frac{x'+vt'}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

                           y=y'

                           z=z'

                        t=\frac{t'+\frac{v}{c^{2}}x'}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

First we calculate the expression in the denominator

                            \frac{v^{2}}{c^{2}}=\frac{(0,70)^{2}c^{2}}{c^{2}} =(0,70)^{2}

                                \sqrt{1-\frac{v^{2}}{c^{2}}} =0,714

then we calculate t

                      t=\frac{t'+\frac{v}{c^{2}}x'}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

                      t=\frac{190s+\frac{0,70c}{c^{2}}.3,4x10^{10}m}{0,714}

                      t=\frac{190s+\frac{0,70c .3,4x10^{10}m}{299792458\frac{m}{s}}}{0,714}

                      t=\frac{190s+79,388s}{0,714}

finally we get that

                                     t=377,29s

then we calculate x

                         x=\frac{x'+vt'}{\sqrt{1-\frac{v^{2}}{c^{2}}}}

                         x=\frac{3,4x10^{10}m+0,70c.190s}{0,714}}

                         x=\frac{3,4x10^{10}m+0,70.299792458\frac{m}{s}.190s}{0,714}}

                         x=\frac{3,4x10^{10}m+39872396914m}{0,714}}

                         x=\frac{73872396914m}{0,714}}

                         x=103462740775,91m

finally we get that

                                     x \approx 103,46x10^{9} m

5 0
4 years ago
Space-shuttle astronauts experience accelerations of about 35 m/s2 during takeoff. What force does a 75 kg astronaut experience
amm1812

Answer:

<h3>The answer is 2625 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 75 × 35

We have the final answer as

<h3>2625 N</h3>

Hope this helps you

5 0
3 years ago
Help me please (。'-‿-。)​
Akimi4 [234]

Answer:

the layers of atmosphere are heated through radiation and convection.

Explanation:

  • heat is transferred from sun through radiation

  • and current through convection
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOMEONE
sasho [114]
I think its B or D, most likely D.
7 0
3 years ago
Other questions:
  • Assume that a person bouncing a ball represents a closed system. Which statement best describes how the amounts of the ball's po
    8·1 answer
  • If an object is moving to the right and there is a net force acting on it to the left, what will happen to the object?
    9·1 answer
  • One hundred turns of insulated copper wire are wrapped around an iron core of cross-sectional area 0.100m2. As the magnetic fiel
    15·1 answer
  • A small sphere is at rest at the top of a frictionless semicylindrical surface. The sphere is given a slight nudge to the right
    5·1 answer
  • When you solve an equation the ___________ of ___________ must be treated like any other mathematical quantity— they must be mul
    13·1 answer
  • Question 14 (2 points)
    5·1 answer
  • An electron traverses a vacuum tube with a length of 2 m in 2 X 10- 4
    12·1 answer
  • For problems 6-9, using the formula net Force = Mass• Acceleration calculate the net force on the object.
    7·1 answer
  • For factors that affect capillarity<br>​
    11·2 answers
  • A ball with an initial velocity of 5 m/s rolls off a horizontal table with a height of 1.0
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!