Answer:
6 km/h
Explanation:
V avg = ∆x/∆t = 3km / 30 min ×(60min/1h) = 3 km× 2 /h = 6 km/h
Answer:
C. Overcome Friction
Explanation:
When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%
Answer:
-1500 m/s2
Explanation:
So the ball velocity changes from 10m/s into the wall to -8m/s in a totally opposite direction within a time span of 0.012s. Then we can calculate the average acceleration of the ball as the change in velocity over a unit of time.
![a = \frac{\Delta v}{\Delta t} = \frac{-8 - 10}{0.012} = \frac{-18}{0.012} = -1500 m/s^2](https://tex.z-dn.net/?f=%20a%20%3D%20%5Cfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D%20%3D%20%5Cfrac%7B-8%20-%2010%7D%7B0.012%7D%20%3D%20%5Cfrac%7B-18%7D%7B0.012%7D%20%3D%20-1500%20m%2Fs%5E2)
YES, ELECTRICITY CONCERNS ENERGY WHICH IS USED AS A FUEL . IN MODERN DAY TECH, MOST MACHINES USE ELECTRICITY AS A FUEL SUCH AS THE ELECTRONIC TRAIN IN TOKYO, JAPAN.
Answer:
The bullet's initial speed is 243.21 m/s.
Explanation:
Given that,
Mass of the bullet, ![m_b=11\ g=0.011\ kg](https://tex.z-dn.net/?f=m_b%3D11%5C%20g%3D0.011%5C%20kg)
Mass of the pendulum, ![m_p=19\ kg](https://tex.z-dn.net/?f=m_p%3D19%5C%20kg)
The center of mass of the pendulum rises a vertical distance of 10 cm.
We need to find the bullet's initial speed if it is assumed that the bullet remains embedded in the pendulum. Let it is v. In this case, the energy of the system remains conserved. The kinetic energy of the bullet gets converted to potential energy for the whole system. So,
V is the speed of the bullet and pendulum at the time of collision
Now using conservation of momentum as :
Put the value of V from equation (1) in above equation as :
![v=\dfrac{(m_p+m_b)}{m_b}\sqrt{2gh} \\\\v=\dfrac{(1.9+0.011)}{0.011}\sqrt{2\times 9.8\times 0.1}\\\\v=243.21\ m/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B%28m_p%2Bm_b%29%7D%7Bm_b%7D%5Csqrt%7B2gh%7D%20%5C%5C%5C%5Cv%3D%5Cdfrac%7B%281.9%2B0.011%29%7D%7B0.011%7D%5Csqrt%7B2%5Ctimes%209.8%5Ctimes%200.1%7D%5C%5C%5C%5Cv%3D243.21%5C%20m%2Fs)
So, the bullet's initial speed is 243.21 m/s.