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2 years ago

Caleb is investigating the effect of friction on the motion of an object. He uses the following supplies for the investigation:

Physics

1 answer:

Annette [7]2 years ago

7 0

Part a
Place the ramps on the floor and time each ramp for time it takes for wooden block too reach thee floor. The times will be different and thus you can conclude that friction will increase the time
Part b
Caleb uses the same block as this is his control variable that he wants to keep same so that the results are correct and accurate
Part c
The independent variable is the thing you change before you test so it will be the surface on which the wooden block is sliding
The dependent variable is the variable you measure so that will be the time it takes for the block to slide to the bottom.

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You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th

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<u>Answer:</u> The Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

$Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}$

where,

Y = Young's Modulus

F = force exerted by the weight = $m\times g$

m = mass of the ball = 10 kg

g = acceleration due to gravity = $9.81m/s^2$

l = length of wire = 2.6 m

A = area of cross section = $\pi r^2$

r = radius of the wire = $\frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m$ (Conversion factor: 1 m = 1000 mm)

$\Delta l$ = change in length = 1.99 mm = $1.99\times 10^{-3}m$

Putting values in above equation, we get:

$Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2$

Hence, the Young's modulus for the wire is $6.378\times 10^{10}N/m^2$

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3 years ago

The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from

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Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

The refore the sound intensity from the orchestra is like 100 times that of the violin.

Explanation:

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Answer:

i think the answer is 12 ohms

plz mark me as brainliest :)

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