Question

7. A wrench falls from a helicopter that is rising steadily at +6.0 m/s.

Answer 1

A. The initial velocity of the wrench is + 6 m/s

B. The velocity of the wrench at two seconds is 13.6 m/s downward

C. The wrench is at 7.6 meters from the release point after 2 seconds

D. The wrench is 19.6 meters below the helicopter after 2 seconds

Explanation:

A wrench falls from a helicopter that is rising steadily at +6.0 m/s

1. The speed of the helicopter is 6 m/s

2. The initial speed of the wrench is the same speed of the helicopter

A.

The initial velocity of the wrench is  + 6 m/s

B.

The velocity after 2 seconds can be get by using the rule:

→ v = u + gt

where v is the final velocity u is the initial velocity, g is the

acceleration of gravity and t is the time

→ u = 6 m/s , t = 2 seconds , g = -9.8 m/s²

→ v = 6 - 9.8(2) = -13.6 m/s

Negative sign means the direction of velocity is downward

The velocity of the wrench at two seconds is 13.6 m/s downward

C.

We can find the distance that the wrench releases by using the rule:

→ s = ut + $\frac{1}{2}$ g t²

where s is the distance

→ u = 6 m/s , g = -9.8 m/s² , t = 2

→ s = 6(2) - $\frac{1}{2}$ (9.8)(2)²

→ s = 12 - 19.6 = -7.6 meters

We will ignore the negative sign because distance is a scalar quantity

The wrench is at 7.6 meters from the release point after 2 seconds

D.

The distance covered by the helicopter is the speed of the helicopter

Multiplied by the time

→ The speed of the helicopter is 6 m/s

→ The time is 2 seconds

→ The distance covered by the helicopter = 6 × 2 = 12 meters

→ The distance covered by the wrench is 7.6 meters

The total distance is the sum of the distance covered by the

helicopter and the distance covered by the wrench

→ The total distance = 7.6 + 12 = 19.6 meters

The wrench is 19.6 meters below the helicopter after 2 seconds

Learn more:

You can learn more about the free fall motion in brainly.com/question/5531630

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