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Paha777 [63]
2 years ago
11

If I want to calculate the normal force of an object on two legs but the weight of the object is not uniform throughout, how do

I go about calculating such a problem?
Physics
1 answer:
RoseWind [281]2 years ago
6 0

Use the right equation. To calculate the normal force of an object at an angle, you need to use the formula: N = m * g * cos (x) For this equation, N refers to the normal force, m refers to the object's mass, g refers to the acceleration of gravity, and x refers to the angle of incline.

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A caterpillar tries to climb straight up a wall a meter high, but for every 2 cm up it climbs, it slides down 1 cm. Eventually,
tiny-mole [99]

<u>Answer:</u>

Total displacement traveled = 298

<u>Explanation:</u>

According to the given information, to actually climb for 1 cm, the caterpillar has to travel for 3 cm (2 cm upwards and 1 cm downwards).

So in order to climb straight up a one meter (100 cm) high wall, it needs to travel for 99 × 3 = 297 cm.

Then after a little it can travel up another cm to reach the top.

Therefore, the total displacement traveled = 297 + 1 = 298 cm

5 0
4 years ago
Read 2 more answers
A ball with a horizontal speed of 1.0m/s rolls off a bench 2.0 m high. (a) how long will the ball take to reach the floor? (b) h
bixtya [17]
The motion of the ball is a composition of two motions:
- on the x (horizontal) axis, it is a uniform motion with initial velocity v_x = 1.0 m/s
- on the y (vertical) axis, it is a uniformly accelerated motion with acceleration g= 9.81 m/s^2 

(a) to solve this part, we just analyze the motion on the vertical axis. The law of motion here is
y(t) = h - \frac{1}{2} gt^2
By requiring y(t)=0, we find the time t at which the ball reaches the floor:
h- \frac{1}{2}gt^2=0
t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2\cdot 2.0 m}{9.81 m/s^2} }=0.64 s

(b) for this part, we can analyze only the motion on the horizontal axis. To find how far the ball will land, we must calculate the distance covered on the x-axis, x(t), when the ball reaches the ground (so, after a time t=0.64 s):
x(t) = v_x t = (1.0 m/s)(0.64 s)=0.64 m
4 0
3 years ago
True or false questions for work and power.​
dalvyx [7]

Answer:

lo escribes en español?

Explanation:

no hablo ingles

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3 years ago
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Rainbow [258]
<span>Copernicus decided this with more of an educated guess than anything. For example is when your standing right next to a plane it's huge Right? Well when it's flying it looks really small. He used the same reasoning for stars. Since it looks small it must be farther away.</span>
8 0
3 years ago
A 4.5 kg mass is accelerated at 40 m/s/s what is the force that was applied
cestrela7 [59]

Answer:

180 N

Explanation:

Use Newton's second law, F = ma.

m = 4.5 kg; a = 40 m/s/s

F = (4.5)(40) = 180 N

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4 years ago
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