Umm. . . Could you list some options? :)
Answer:
a. HI(aq)+NaOH(aq) → H2O(l)+NaI(aq)
b. HBr(aq) +KOH(aq) → H2O(l)+KBr(aq)
c. HNO3(aq)+Ba(OH)2(aq) → BaNO3(aq)+H2O(aq)
D. HClO4(aq)+Sr(OH)2(aq) → SrClO4(aq)+H2O(aq)
Explanation:
In a neutralization reaction, an acid and a base react to form water and salt and involves the combination of H+ ions and OH- ions to generate water.
In this case, the atoms have charge positive and negative, the only thing we have to do is to change in the products taking account that positive with negative an vice-versa.
H+I-(aq)+Na+OH-(aq) → H+2O-(l)+Na+I-(aq)
Answer:
You use the fact that 1 mole of any substance contains exactly 6.022⋅1023 atoms or molecules of that substance - this is known as Avogadro's number. In your case, 1 mole of gold will have exactly 6.022⋅1023 atoms of gold.
So it would be answer 3690 atoms or 3.60x1025