Answer:
Explanation:
moles of acetic acid = 500 x 10⁻³ x .1 M
= 5 X 10⁻³ M
.005 M
Moles of NaOH = .1 M
Moles of sodium acetate formed = .005 M
Moles of NaOH left = .095 M
pOH = 4.8 + log .005 / .095
= 4.8 -1.27875
= 3.52125
pH = 14 - 3.52125
= 10.48
It is photosynthesis
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photosynthesis is the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct, hope it helps</span>
Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
Explanation : Given,
Mass of oxygen in sulfur dioxide = 3.49 g
Mass of sulfur in sulfur dioxide = 3.50 g
Mass of oxygen in sulfur trioxide = 9.00 g
Mass of sulfur in sulfur trioxide = 6.00 g
Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.
Mass of oxygen per gram of sulfur for sulfur dioxide = 
Mass of oxygen per gram of sulfur for sulfur dioxide = 
and,
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
The number of electrons that can occupy the sub levels being filled by that period
Answer:
It is known generally that polar compounds are soluble in polar solvents. Based on the structure of benzoic acid, it comprises the non-polar C6H6 group and polar COOH group. Based on the structure, in benzoic acid, the nonpolar hydrocarbon outweighs and influences the polar part as nonpolar, due to which benzoic acid is not soluble in water.
On the other hand, benzoic acid produces sodium salt benzoic acid when it reacts with 2.5 M sodium hydroxide, this salt is ionic. Generally, the ionic compounds are soluble in water. Therefore, the salt of benzoic acid gets dissolved in water. Hence, benzoic acid is soluble in the solution of sodium hydroxide.