Answer:A)For open pipe
1stπ=484cm
2nd wavelength=161.3cm
3rd is=96.8cm
B)For closed pipe
1st wavelength=242cm
2nd=121cm
3rd wavelength=80.7cm
Explanation:
An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...
So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4
π= 121×4=484cm
Third harmonic,L=3π /4
So π= 4l/3=4×121/3=161.3cm
The 3rd wavelength is
Fifth harmonic=
π =4l/5=4×121/5=96.8cm
For a pipe open at one end and closed at the other also called closed pipe
Fundamental note is
2L/n= π where n=1,2,3....ie integers
First wavelength
π=2L=2×121=242cm
Second wavelength
π=L=121cm
Third is
π=2L/3=2×121/3=80.7cm
Here volume of gas is not given so question is solved assuming volume as 1 L.
The number of moles of 1 L gas present in the sealed container at a
pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.
The ideal gas law equation can be written as
PV = nR T
Here
P is the pressure of the gas in atm
V is the volume it occupies in L
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821 atm L/ mol K
T is the absolute temperature of the gas in Kelvin
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
So
P = 125 kPa
1 atm = 760 kPa
P = 125/760 = 0.1644 atm
T = 25 degree celsius = 25 +273 = 298 K
Taking V = 1 L
So
n = PV/RT
n = 0.1644 x 1 / 0.0821 x 298
n = 0.0067 moles
To learn more about the ideal gas law, please click on the link brainly.com/question/128737528
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there it is fella tried on ma own consciousness
I believe it’s power, but i could be wrong!
E = q/r^2
where r is perpendicular distance between the point and source charge
Ex = E cos theta
Ey = E sin theta
take theta angle between horizontal and line joining the point charge and the point