To bring something to a stop the same force that was applied to speed it up can be used to stop it. If a greater force is used it will stop quicker.
I would say Emotional health. Just because it is more sensable
Answer:
Pressure applied to the needle is 7528 Pa
Explanation:
As we know by poiseuille's law of flow of liquid through a cylindrical pipe
the rate of flow through the pipe is given as

now we know that

radius = 0.2 mm
Length = 6.32 cm

now we have



now we have


Voltmeter is used to find the potential difference between two points.
We always connect it in parallel to the points where we need the potential difference.
Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.