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Nadusha1986 [10]
2 years ago
12

How many argon (ar) atoms are there in 1.5 × 102 g of argon?

Chemistry
1 answer:
Setler [38]2 years ago
8 0
Answer is: there is 2,25·10²⁴ argon atoms.
m(Ar) = 1,5·10² g = 150 g.
n(Ar) = m(Ar) ÷ M(Ar).
n(Ar) = 150 g ÷ 40 g/mol.
n(Ar) = 3,75 mol.
N(Ar) = n(Ar) · Na.
N(Ar) = 3,75 mol · 6·10²³ 1/mol.
N(Ar) = 2,25·10²⁴.
n - amount of substance.
Na - Avogadro number.
M - molar mass of atom.
m - mass of atom.
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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
natima [27]

Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • N₂: 1 mole
  • H₂: 3 moles
  • NH₃: 2 moles

The molar mass of the compounds is:

  • N₂: 14 g/mole
  • H₂: 2 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×14 g/mole= 14 grams
  • H₂: 3 moles ×2 g/mole= 6 grams
  • NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

4 0
2 years ago
Part B When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8 g of carbon were burned in the pres
aksik [14]

<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carbon = 22.8 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol

The chemical equation for the reaction of carbon and oxygen gas follows:

C+O_2\rightarrow CO_2

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = \frac{1}{1}\times 1.9=1.9moles of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.9 moles

Putting values in equation 1, we get:

1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g

Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams

6 0
2 years ago
10. Carbon tetrachloride has a density of 1.60 g/mL. What is the volume of 40 grams of CCl4?
ikadub [295]

Answer:

The answer is

<h2>25 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass of CCl4 = 40g

Density = 1.6 g/mL

The volume is

volume =  \frac{40}{1.6}

We have the final answer as

<h3>25 mL</h3>

Hope this helps you

5 0
3 years ago
How are mass and gravitational pull related?
V125BC [204]

Answer:

yes/no

Explanation:

i have no clue.

6 0
3 years ago
Read 2 more answers
The table shows the charge on three unknown subatomic particles.
brilliants [131]

Answer:

B. only particle Z

Explanation:

In the case of subatomic particles, those positive and neutral are located in the nucleus, and those with a negative charge on the outside.

8 0
3 years ago
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