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PilotLPTM [1.2K]
2 years ago
9

2.)If a chemical reaction such as photosynthesis begins with 6 atoms of carbon (C), how many atoms of carbon (C) should be in th

e products?
Chemistry
1 answer:
12345 [234]2 years ago
4 0

Answer:

3 atoms of carbon

Explanation:

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Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-
Karolina [17]

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

  • 113.4 g ÷ 46 g/mol = 2.465 mol

Then we<u> use the PV=nRT formula</u>, where:

  • P = 1atm & T = 273K (This means STP)
  • n = 2.465 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • V = ?

Input the data:

  • 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And <u>solve for V</u>:

  • V = 55.18 L
6 0
2 years ago
A sample of nitrogen gas is produced in a reaction and collected under water in a graduated cyliner. The temperature is 26.3 oC
Rudiy27

The mass of nitrogen collected is mathematically given as

M-N2=0.025gram

<h3>What is the mass of nitrogen collected?</h3>

Question Parameters:

A sample weighing 2.000g

the liberated NH3 is caught in  50ml pipeful  of H2SO4 (1.000ml   =  0.01860g Na2O).

T=26.3c=299.3K

Pressure=745mmHg=745torr

Pressure of N2=745-25.2=719.8torr

Generally, the equation for the ideal gas   is mathematically given as

PV=nRT

Therefore

719.8/760=45.6/1000=n*0.0821*299.3

n=0.00176*14

In conclusion, the Mass of N2

M-N2=0.00176*14

M-N2=0.025gram

Read more about Mass

brainly.com/question/4931057

8 0
2 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion:
siniylev [52]

Answer : The reaction rate will be, 1.9\times 10^{-4}M/s

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2HgCl_2(aq)+C_2O_2^{4-}(aq)\rightarrow 2Cl^-(aq)+2CO_2(g)+HgCl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_2^{4-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_2^{4-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b ....(4)

Dividing 1 from 2, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{k(0.164)^a(0.45)^b}{k(0.164)^a(0.15)^b}\\\\9=3^b\\(3)^2=3^b\\b=2

Dividing 3 from 2, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{k(0.164)^a(0.45)^b}{k(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2

Now, calculating the value of 'k' by using any expression.

Putting values in above rate law, we get:

3.2\times 10^{-5}=k(0.164)^1(0.15)^2

k=8.7\times 10^{-3}M^{-2}s^{-1}

Now we have to determine the reaction rate when the concentration of HgCl_2 is 0.135 M and that of C_2O_2^{-4} is 0.40 M.

\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2

\text{Rate}=(8.7\times 10^{-3})\times (0.135)^1\times (0.40)^2

\text{Rate}=1.9\times 10^{-4}M/s

Therefore, the reaction rate will be, 1.9\times 10^{-4}M/s

6 0
3 years ago
Write any five example of radical with their velencies​
garri49 [273]

Answer:

Terms in this set (13)

Hydroxide. OH.

Nitrate. NO3.

Ammonium. NH4.

Bicarbonate/Hydrogen Carbonate. HCO3.

Bisulphate. HSO4.

Chlorate. ClO3.

<h2>hope it's correct</h2>

7 0
2 years ago
Help asap plzzzz 30 points
Rus_ich [418]

Answer:

Do you need your 0.00 2 oz

Explanation:

Because that is the right answer

4 0
3 years ago
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