Answer:
The object will be sank
Explanation:
In this case the object is more dense than water.
Density is the relationship between a certain amount of mass of matter and the volume that is being occupied by it.
The object occupies more volume, so it occupies more mass.
As the mass from the object is higher, the object will be sank because the weight is higher than the weight from the liquid.
If the object has a lower density than the water, it will float on it.
Answer:
no, and next time take it right
Explanation:
The number of moles of the magnesium (mg) is 0.00067 mol.
The number of moles of hydrogen gas is 0.0008 mol.
The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.
<h3>
Number of moles of the magnesium (mg)</h3>
The number of moles of the magnesium (mg) is calculated as follows;
number of moles = reacting mass / molar mass
molar mass of magnesium (mg) = 24 g/mol
number of moles = 0.016 g / 24 g/mol = 0.00067 mol.
<h3>Number of moles of hydrogen gas</h3>
PV = nRT
n = PV/RT
Apply Boyle's law to determine the change in volume.
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (101.39 x 146)/(116.54)
V2 = 127.02 mL
Now determine the number of moles using the following value of ideal constant.
R = 8.314 LkPa/mol.K
n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)
n = 0.0008
<h3>Volume of 1 mole of hydrogen gas at STP</h3>
V = nRT/P
V = (1 x 8.314 x 273) / (101.325)
V = 22.4 L
Learn more about number of moles here: brainly.com/question/13314627
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<u>Answer:</u> The molality of the solution is 0.11 m
<u>Explanation:</u>
We are given:
Mole fraction of methanol = 0.135
This means that 0.135 moles of methanol is present in 1 mole of a solution
Moles of ethanol = 1 - 0.135 = 0.865 moles
To calculate the mass for given number of moles, we use the equation:
Moles of ethanol = 0.865 moles
Molar mass of ethanol = 46 g/mol
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (methanol) = 0.135 g
= Molar mass of solute (methanol) = 32 g/mol
= Mass of solvent (ethanol) = 39.79 g
Putting values in above equation, we get:
Hence, the molality of the solution is 0.11 m