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3 years ago

Calculate the change in entropy if Br2(l) is converted to Br2(g).

Chemistry

1 answer:

Alik [6]3 years ago

5 0

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

= 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

= 1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K

= 93.3 J/K

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Calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting tota

Ghella [55]

Answer:

(a) Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = -2.881 J/K; total change in entropy = 0

(b)Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = 0 ; total change in entropy = 2.881 J/K

Explanation:

In the given problem, we need to calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting total change in entropy, when a sample of nitrogen gas of mass 14 g at 298 K and 1.00 bar doubles its volume. We have the following variable:

mass (m) = 14 g

Temperature = 298 K

Pressure = 1.00 bar

Initial volume = $V_{1}$

Final volume = $V_{2}$ = $2V_{1}$

(a) Change in entropy of the system Δ $S_{sys}$ = $nRIn\frac{V_{2} }{V_{1} }$

where R = 8.314 J/(mol*K)

n = number of moles = mass/molar mass = 14/ 28 = 0.5 moles

Δ $S_{sys}$ = 0.5*8.314*ln2 = 2.881 J/K

Change in entropy of the surrounding Δ $S_{sur}$ = -2.881 J/K

Therefore, for a reversible process, the total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 2.881 - 2.881 = 0

(b) Because entropy is a state function, we use the same procedure as in part (a). Thus, Δ $S_{sys}$ = 2.881 J/K

Since surrounding does not change in this process Δ $S_{sur}$ = 0.

total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 2.881 - 0 = 2.88 J/K

Δ $S_{sys}$ = 0

Since heat energy is not transferred from the system to the surrounding

Δ $S_{sur}$ = 0

total change in entropy = Δ $S_{sys}$ +Δ $S_{sur}$ = 0

6 0

2 years ago

What is dynamic equilibrium? What is dynamic equilibrium? Dynamic equilibrium in a chemical reaction is the condition in which t

OverLord2011 [107]

Answer:

The correct answer is: Dynamic equilibrium in a chemical reaction is the condition in which the rate of the forward reaction equals the rate of the reverse reaction.

Explanation:

Dynamic equilibrium is a chemical equilibrium between froward reaction and backward or reverse reaction where rate of reaction going forwards is equal to the rate of reaction going backward (reverse).

Some other properties of dynamic equilibrium are:

Chemical equilibrium are attained is closed system.
The macroscopic remains constant like: volume, pressure, energy etc.
The concentration of the reactants and products remain constant.They are not always equal.

7 0

3 years ago

If a mixture containing 0.50 moles of N2 and 1.8 moles of H2 is allowed to react according to the equation N2 3H2 2NH3 Group of

Lelechka [254]

Answer: hydrogen is the limiting reactant.

Explanation:

We have the equation $\text{N}_{2}+3\text{H}_{2} \longrightarrow 2\text{NH}_{3}$ .

This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

Considering the nitrogen, the reaction can occur 0.50 times.
Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.

Therefore, hydrogen is the limiting reactant.

7 0

2 years ago

Compare Ion and Radical Atom and molecule Organic and inorganic compounds

horrorfan [7]

Answer:

'An ion has a non-zero electric charge. A radical has an atom with unfilled electron shells and so is very reactive, but is electrically neutral.'

'Atoms are single neutral particles. Molecules are neutral particles made of two or more atoms bonded together.'

'The primary difference that lies between these organic compounds and inorganic compounds is that organic compounds always have a carbon atom while most of the inorganic compounds do not contain the carbon atom in them.'

6 0

1 year ago

Read 2 more answers

How can constraints be used to help define the problem?

vitfil [10]

Answer:

Constraints are restrictions that need to be placed upon variables

Explanation:

Constraints are restrictions (limitations, boundaries) that need to be placed upon variables used in equations that model real-world situations. It is possible that certain solutions which make an equation true mathematically, may not make any sense in the context of a real-world word problem.

6 0

3 years ago