The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the following Charle's law equation:
V1/T1 = V2/T2
Where;
- T1 = initial temperature
- T2 = final temperature
- V1 = initial volume
- V2 = final volume
- V1 = 9L
- V2 = ?
- T1 = 325K
- T2 = 450K
9/325 = V2/450
325V2 = 4050
V2 = 4050/325
V2 = 12.46L
Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
Learn more about volume at: brainly.com/question/2817451
4.17 moles. Good luck! :)
Answer: 0, 32 , 273
Explanation:
The freezing point of water in degree Celsius, Fahrenheit and Kelvin are in the following order; 0 , 32 , 273
1. Humidity
2. Temperature
3. Rainfall
In general, the electron pairs in a molecule that will adopt a shape to maximize their distance far apart, even charges repel each other as well as unlike charges attract,
for example H2O has two lone electrons pairs but it adopts an angular shape. Hope this help!!
