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patriot [66]
3 years ago
14

I beg you to help me in this and im gonna mark u as brainliest but fassttt

Chemistry
2 answers:
Anni [7]3 years ago
6 0

Explanation:

F = nucleus

G = cell membrane

H = cytoplasm

J = cell wall

k = vacoule

L = plastids

mark me brainiest?

Dovator [93]3 years ago
3 0
F- nucleus
G-cell membrane
H- cytoplasm
J-cell wall
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2 H2 + O2= 2 H2O
AVprozaik [17]

Answer:

the answer is 4.0moles

Explanation:

1mole of O2 produce 2moles of H2O/x mole will produce 8.0moles of H2O then the answer is 4.0moles.

3 0
3 years ago
5. What could you do to convert from meters to centimeters? *
maria [59]

C.

centi- is essentially 10^2 of one meter.

If you had 100m, multiplying 100 by 10^2 (or 100) would give you 10000 cm.

7 0
3 years ago
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Explain the following phenomena. why Fluorine has lower electron affinity than chlorine​
Radda [10]

Electron affinity for fluorine is than chlorine most likely , due to the electron repulsion that occur between the electron where n= 2 . the elements in the second period have such small electron clouds that electron repulsion is greater than that of the rest of the family.

4 0
3 years ago
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Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4?
nekit [7.7K]

Answer:

18.33 ×10²³ atoms

Explanation:

Given data:

Molar mass of sulfuric acid = 98.1 g/mol

Mass of sulfuric acid = 75.0 g

Number of of oxygen atom present = ?

Solution:

Number of moles of sulfuric acid:

Number of moles = mass/molar mass

Number of moles = 75.0 g/ 98.1 g/mol

Number of moles =0.761 mol

one mole of  sulfuric acid  contain four mole of oxygen atom.

0.761 mol × 4 = 3.044 mol

1 mole = 6.022×10²³ atoms of oxygen

3.044 mol ×  6.022×10²³ atoms of oxygen / 1mol

18.33 ×10²³ atoms

3 0
3 years ago
Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has
bija089 [108]
<h2>Answer:</h2>

Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic  \: mass }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 72 \times84.9 + 28 \times 87  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 6112.8 + 2436  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 8548.8  }{100} \\

\footnotesize \longrightarrow \:  \bf Average \:  atomic  \: mass =  85.488 \: amu  \\

8 0
2 years ago
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