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andreyandreev [35.5K]
3 years ago
8

Why does a magnet exert a force on another magnet when the two magnets are not in contact?

Physics
2 answers:
Sladkaya [172]3 years ago
6 0
It's due to electromagnetism
A magnet is surrounded by a magnetic field that exerts the magnetic force. The magnetic field is strongest closer to the magnet
Orlov [11]3 years ago
4 0

The two magnets when in close proximity experiences the force upon each other being applied by one another because of the electromagnetic field.

<u>Explanation:</u>

The magnets have the property of electromagnetism which is induced by the particles of the magnet with the presence of electrons. The magnet have electromagnetic field around them which are stronger in close proximity and grows weaker as the distance increases.

So when the two magnets are in proximity experiences the force without actual contact between the two said magnets.

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Which of the following particles is NOT a candidate for dark matter?
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its C) Axion                        

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A girl who is watching a plane fly tells her friend that the plane isn't moving at all. Describe a frame of reference in which t
Dafna1 [17]
If the plane is far away and flying directly toward or away from
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6 0
3 years ago
Read 2 more answers
A vector has an x component of -27.5 units and a y component of 41.4 units. Find the magnitude and direction of this vector. mag
evablogger [386]

Answer:

a.) magnitude __49.7__ unit(s)

b.) direction __123.6°_  counterclockwise from the +x axis

Explanation:

Let Vector is v

x-component of Vector v = x = -27.5 units   (minus sign indicate that x-component is along the minus x-axis )

y-component of Vector v = y = 41.4 units

Magnitude of v = ?

Direction of v = ?

To find the magnitude of the vector

                                     v =\sqrt{x^{2}+y^{2}  }  

                                     v = \sqrt{-27.5^{2}+41.4^{2} }

                                     v = 49.7 units  

To find direction

                                 θ = tan⁻¹(y/x)

                                 θ = tan⁻¹(41.4/-27.5)

                                 θ = -56.4°

This Angle is in the clockwise direction with respect to -x axis.

We need to find Angle counterclockwise from the +x axis.

So,

                                 θ = 180° - 56.4°

                                 θ = 123.6°                

The given vector is in 2nd quadrant

4 0
4 years ago
HELP!!
QveST [7]

Answer:

Total displacement 155 m

Explanation:

From the question, the formula to apply will be that of cosine rule where:

c=\sqrt{a^2+b^2-2ab*cosC}

where

a= 43 m , b=130m and c =? , <C=28° + 90° =118°

Substituting values in the equation as;

c=\sqrt{43^2+130^2-2*43*130*cos118}

c=\sqrt{1849+16900-11180*-0.46947} \\\\c=\sqrt{1849+16900+5249} \\\\c=\sqrt{23998} \\\\\\c=155m

6 0
3 years ago
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