Interesting question. I'd take a guess that it could be either mirrors and light travelling in straight lines and being reflected, or optical fibres to achieve a perhaps similar result.
Answer:
10392.30N
Explanation:
We proceed by computing the individual force exerted by the boats
For the first boat
The angle is 30 degree to the vertical
Hence
Force = F cos θ
F=6000 cos 30
F=6000*0.866
F=5196.15 N
Since the boats are two and also at the same angle and also exerting the same force
The Net force = 2*5196.15
Net force=10392.30N
Q1. The answer is 8.788 m/s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V1 = 4.7 m/s
a = 0.73 m/s²
t = 5.6 s
V2 = ?
V2 = 4.7 + 0.73 * 5.6
V2 = 4.7 + 4.088
V2 = 8.788 m/s
Q2. The answer is 9.22 s
V2 = V1 + at
V1 - the initial velocity
V2 - the final velocity
a - the acceleration
t - the time
We have:
V2 = 0 (because it reaches a complete stop)
V1 = 4.7 m/s
a = -0.51 m/s²
t = ?
0 = 4.7 + (-0.51)*t
0 = 4.7 - 0.51t
0.51t = 4.7
t = 4.7 / 0.51
t = 9.22 s
