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Cloud [144]
3 years ago
5

A box moves 5m horizontally when force F=10N is applied at an angle 0=30°.

Physics
1 answer:
True [87]3 years ago
7 0

Answer:

43.3J

Explanation:

Given parameters:

Force  = 10N

Distance  = 5m

Angle  = 30°

Unknown:

Work done  = ?

Solution:

Work done is the force applied to move a body through a particular distance;

 Work done  = Force x distance cos Ф

Now insert the parameters and solve;

     Work done  = 10  x 5 cos 30 = 43.3J

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Make sure everything is organized have a planner it can help

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Si pudieras viajar a la Luna:
Nostrana [21]

Answer:

i) Distancia, ii) La cinta métrica es impracticable.

Explanation:

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La distancia puede involucrar trayectorias curvilíneas entre los puntos mencionados.

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En este caso, es mejor utilizar la medición con tecnología láser, basadas en el fenómeno del electromagnetismo.

4 0
3 years ago
I need help on the data section of the circuit design lab on Edg.
Arte-miy333 [17]

I hope it's not too late, but here you go

8 0
3 years ago
A binary star system consists of two equal mass stars that revolve in circular orbits about their center of mass. The period of
Vladimir79 [104]

Answer:

m = 2.23 \times 10^{-32} kg

Explanation:

Given data:

PERIOD OF MOTION IS T = 25.5 days

orbital speeds = 220 km/s

we know that

acceleration due to centripetal force isa =   \frac{F}{m} = \frac{V^2}{r}

Gravitational forceF= \frac{Gm m}{d^2}

we know that

v = \frac{2\pi R}{T}

solving for

R = \frac{vT}{2\pi}

F = \frac{Gm^2}{4(\frac{vT}{2\pi})^2}

F = G\times \frac{\pi m}{(vT)^2}

a = \frac{v^2}{\frac{vT}{2\pi}}

a = \frac{2\pi v}{T}

we know that

f =ma

G\times \frac{\pi m}{(vT)^2} = a = \frac{2\pi m v}{T}

solving for m

m = \frac{2Tv^3}{\pi G}

m = \frac{2\times 25.5 \times 86400 \times 220000^3\ m/s}{\pi \times 6.67\times 10^{-11}}

m = 2.23 \times 10^{-32} kg

5 0
3 years ago
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