All categories

3 years ago

What are two ways you can change atomic mass

Physics

1 answer:

e-lub [12.9K]3 years ago

4 0

Atomic mass can change through the process of fusion. Another way is, it can also change in nuclear fusion.

You might be interested in

An object (initially at rest) is dropped from a height h above the ground if it takes 4 seconds for the object to reach the grou

seraphim [82]

Since U=0,
h=1/2gt^2 (h= ut+1/2gt^2, U=0)
h=1/2*10*4*4
h=80m

8 0

2 years ago

In a milkans apparatus,an oil drop of weight 2.0×10^-15kg accquires two surplus electrons. when a Potential difference of 620 vo

andriy [413]

Answer:

r = 9.92 mm

Explanation:

Given that,

Mass of oil drop, $m=2\times 10^{-15}\ kg$

It acquires 2 surplus electrons, q = +2e $=3.2\times 10^{-19}\ C$

Potential difference, V = 620 V

Thie potential difference is applied between the pair of horizontal metal plates the drop is in equilibrium.

We need to find the distance between the plates.

At equilibrium,

mg = qE

Since, E = V/r (r is distance between plates)

$mg=\dfrac{qV}{r}\\\\r=\dfrac{qV}{mg}\\\\r=\dfrac{3.2\times 10^{-19}\times 620}{2\times 10^{-15}\times 10}\\\\=0.00992\ m\\\\=9.92\ mm$

So, the distance between the plates is 9.92 mm.

6 0

2 years ago

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 3

Lelu [443]

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L = 330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

8 0

2 years ago

A gamma ray burst produces radiation that has a period of 3.6x10-21 s. What wavelength does this radiation have?

Olin [163]

Answer:

The radiation wavelength is 1.08 X 10⁻¹² m

Explanation:

Frequency is the ratio of speed of photon to its wavelength

F = c/λ

where;

c is the speed of the photon = 3 x 10⁸ m/s

λ is the wavelength of gamma ray = ?

F is the frequency of the gamma ray = 1/T

T is the period of radiation = 3.6x10⁻²¹ s

$\frac{1}{T} = \frac{c}{\lambda}$

λ = T*C

λ = 3.6x10⁻²¹ * 3 x 10⁸

λ = 1.08 X 10⁻¹² m

Therefore, the radiation wavelength is 1.08 X 10⁻¹² m

6 0

2 years ago

A vector has what and direction

galben [10]

A vector Quantity has MAGNITUDE and direction, so the ‘what’ is Magnitude.

8 0

3 years ago

Read 2 more answers