The pacific ocean has a surface area of about

What happens if you cut a bar magnet in half between the north and south poles?

Valentin [98]

Answer:

C

Explanation:

A magnet is basically a bundle of tiny magnets,magnetic domains. Each one has a tiny north and south pole. If you cut one in half, the newly cut faces will become the new north or south poles of the smaller pieces.

4 0

3 years ago

Read 2 more answers

Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in one

Allushta [10]

Answer:

total number of electron in 1 litter is 3.34 × $10^{26}$ electron

Explanation:

given data

mass per mole = 18 g/mol

no of electron = 10

to find out

how many electron in 1 liter of water

solution

we know molecules per gram mole is 6.02 × $10^{23}$ molecules

no of moles is 1

so

total number of electron in water is = no of electron ×molecules per gram mole × no of moles

total number of electron in water is = 10 × 6.02 × $10^{23}$ × 1

total number of electron in water is = 6.02× $10^{24}$ electron

and

we know

mass = density × volume ..........1

here we know density of water is 1000 kg/m

and volume = 1 litter = 1 × $10^{-3}$ m³

mass of 1 litter = 1000 × 1 × $10^{-3}$

mass = 1000 g

so

total number of electron in 1 litter = mass of 1 litter × $\frac{molecules per gram mole}{mass per mole}$

total number of electron in 1 litter = 1000 × $\frac{6.02*10{24}}{18}$

total number of electron in 1 litter is 3.34 × $10^{26}$ electron

8 0

3 years ago

Altitude refers to ________________. Group of answer choices the angular distance from the celestial equator the angular height

liraira [26]

In Science, altitude refers to: D. the angular height away from the horizon.

<h3>What is altitude?</h3>

Altitude is also referred to as an elevation and it can be defined as the vertical distance (height) above a natural satellite or the surface of a planet such as land or sea level.

This ultimately implies that, an altitude is vertical height (elevation) of an object or physical body above a particular location or planetary reference plane such as land or sea level on Earth.

In conclusion, altitude is the angular height of an object or physical body away from the horizon.

Read more on altitude here: brainly.com/question/1159693

3 0

2 years ago

A truck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. How strong must the rope be? μk

ExtremeBDS [4]

Answer:

The rope must have a force of 10084,21 N

Explanation:

$ac=ac=\frac{13}{15} \frac{m}{s}$

$ac = at = \frac{13-0}{15-0}$

We replaced the known information in the equation(1):

vi = Initial speed = 0, ti = initial time = 0

Known information:

at: truck acceleration(m/s2)

ac: car acceleration $\frac{m}{s^{2} }$

Kinematic analysis

The car acceleration is equal to the acceleration of the truck because the truck and the car are connected by the rope.

We apply Newton's first law to calculate the Normal force because there is no movement in the vertical direction:

$∑Fy= 0$

$N-W=0$

$N=W$

$N=21854 N$

We replace the values of the mc and g in the equation(2):

$Wc= 2230*9.8$

$Wc=21854 N$

Normal force calculation:

Car weight calculation:

$Wc=mc*g$

mc = Car mass = 2230kg

g = Gravity acceleration=9.8 $\frac{m}{s^{2} }$

Friction force calculation (Ff):

We have the formula to calculate the friction force:

Ff = μk * N Equation (3)

μk: kinetic coefficient of friction

We know that μk = 0.373and N= 21854N , then we replaced this data in(3):

$Ff=0.373*21854$

$Ff=8151.54 N$

Calculation of the tension force in the ro pe (T):

We apply Newton's Second law to calculate the Normal force because there is no movement in the horizontal direction:

$∑Fx= mc*ac$

We take the sense of the forces like this:

positive to the right and negative to the left

$T-Ff=mc*ac$

$T=2230(\frac{13}{15} + 8151.54$

$T=10084,21 N$

Answer: The rope must have a force of 10084,21 N

7 0

4 years ago

Find the total energy (ft-lb) of an aircraft weighing 20,000 lbs at 5,000 ft true altitude and 200 KTS true air speed. Group of

trapecia [35]

Answer:

Hello the options to your question is missing below are the options

2 x 10^8 ft-lb

15527950 ft-lb

2.8 x 10^7 ft-lb

13.55 x 10^7 ft-lb

Answer : 13.55 * 10^7 ft-Ib

Explanation:

Given data :

weight of Aircraft (p) = 20000 Ibs

height ( h ) = 5000 ft

Velocity = 200 KTS = 370 km/h ( 10277 m/s) where 1 KTS = 1185 km/h

calculate the total energy

Total energy = potential energy + kinetic energy

potential energy = mgh = p * h =20000 * 5000 = 100 * 10^6 ft-Ibs

kinetic energy = 1/2 mv^2 = 1/2 * 625 * (33709)^2 = 3551 *10^6 ft-Ibs

where ; m = p/g = 20000 / 32 = 625 Ibs

v = 10277 m/s ≈ 33709 ft/s

hence total energy = 100 * 10^6 + 3551 * 10^6 = 1355*10^7 ft-Ibs

3 0

3 years ago