Answer:
Ni(NO3)2 + 2NaOH → Ni(OH)2 + 2NaNO3
NET IONIC EQUATION :
Ni +2(aq) + 2(NO3) -1(aq) + 2Na +1(aq) + 2OH -1(aq)
→ Ni(OH)2 (s) + 2Na +1(aq) + 2(NO3) -1(aq)
sorry there is no space to write the reaction in one line...
1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.
<h3>How to calculate mass?</h3>
The mass of a substance can be calculated by multiplying the number of moles by its molar mass.
However, the number of moles can be calculated by using the following formula:
Molarity = no of moles ÷ volume
no of moles = 1.75 × 2.5
no of moles = 4.38mol
molar mass of Ba(NO3)2 = 261.34g/mol
mass of Ba(NO3)2 = 261.34 × 4.38
mass of Ba(NO3)2 = 1143.4grams.
Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.
Learn more about mass at: brainly.com/question/19694949
Yeah it depends on what mixture
