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harina [27]
3 years ago
14

After a new

Engineering
1 answer:
dybincka [34]3 years ago
7 0
I think it is B or C
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Elements in the same ____ have the same numbers of valence electrons?
lions [1.4K]
Explanation: For main group elements, the number of valence electrons is the same in every element in the same group. Group 1 elements have 1 valence electron in the s orbital.
8 0
3 years ago
Read 2 more answers
The system is initially moving with the cable taut, the 15-kg block moving down the rough incline with a speed of 0.080 m/s, and
garik1379 [7]

Solution :

The spring is expanded by 2 times of the block when it moves down an inclined by x times.

Here, $x_1$ = 39 mm

        x_2 = 225 mm

a). From the work energy principal,

   Work forces = kinetic energy

$(mg \sin 50^\circ)\times \frac{99}{1000}-(\mu_k mg \cos 50^\circ) \times \frac{99}{1000} -\frac{1}{2}k(0.225^2 - 0.039^2)=\frac{1}{2}m(V^2_2-0.08^2)$

$(112.6 \times 0.099)-(14.17 \times 0.099)-4.91= 7.5(V^2_2-0.08^2)$

$9.75= 7.5(V^2_2-0.08^2)$

$1.3= V^2_2-0.08^2$

$V_2=1.14\ m/s$

b). calculating the distance travelled by the block before it comes to rest.

Substitute the value of V_2 in (1),

$-(\mu_kmg \cos 50^\circ)x + (mg \sin 50^\circ)x-\frac{1}{2}k\left( ( 2x+0.039)^2 - 0.039^2\right)= -\frac{1}{2}m(0.08)^2$

$-14.17x+112.6x - 100(4x^2+0.156x)=-0.048$

$98.43x - 100(4x^2+0.156x)+0.048=0$

$98.43x - 400x^2-15.6x+0.048=0$

$82.83x - 400x^2+0.048=0$

$  400x^2- 82.83x-0.048=0$

x = 0.20 m

4 0
3 years ago
Please calculate the current for the circuit below
Aleks04 [339]

Answer:

The answer is "I = 0.0085106383 \ A"

Explanation:

Given:

R= 470  \ \Omega \\\\V= 4 \ v

Formula:

\to V=IR\\\\\to I = \frac{V}{R}\\\\

      = \frac{4}{470}\\\\ = 0.0085106383 \ A

3 0
3 years ago
Extra Credit: The Linc (parking lot and stadium)In celebration of the upcoming Super Bowl, for a maximum 10 points of extra cred
Sidana [21]

Answer:

Explanation:

// Below is the code to draw parking lot only , i have also put the o/p of code.

import java.util.*;

import java.lang.*;

import java.io.*;

public class Linc

{

static int size=4;

static int numBoxes = 1; // one row.

static int height =(int) Math.pow(size, 2); //Just how many | will it have.

static int width = 2; // two boxes in a row

public static void main (String[] args) throws java.lang.Exception

{

top();

printHeight();

}

  public static void top(){

  for(int i = 0; i <= numBoxes*width;i++)

  {

  if(i%width == 0) {//When this happens we're in a new box.

      System.out.print(" ");

      System.out.print("____________");

  }

  else

  System.out.print(" ");

  }

  System.out.println(); //Move to next line.

 

  }

  public static void printHeight(){

  for(int j = 0; j < height;j++){

  for(int i = 0; i <= numBoxes*width;i++)

  {

  if(i%width == 0) {

  System.out.print("|"); //Whenever this happens we're in a new box.

  System.out.print("____________");

     

  }

  else

  System.out.print(" ");

 

  }

  System.out.print("|");

  System.out.println(); //Move to next line.

  }

  }

}

8 0
3 years ago
What are the rights of people bicycling, under Illinois state law? *
zhuklara [117]

Answer:

○ People biking have the same right to be on the road as motorists, except for roads (such as expressways) where signs prohibit bikes​

Explanation:

MRK ME BRAINLIEST PLZZZZZZZZZZZZZ

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