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skad [1K]
3 years ago
7

There are three homes being built, each with an identical deck on the back. Each deck is comprised of two separate areas. One ar

ea is 112.5 square feet, while the other is
136,4 square feet. What is the total square footage of the decks for all three homos? Your answer should be to the nearest tonth of a square
Engineering
1 answer:
9966 [12]3 years ago
7 0

9514 1404 393

Answer:

  746.7 ft²

Explanation:

You can add them up, or you can take advantage of multiplication to make the repeated addition simpler.

  (112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²) +(112.5 ft² +136.4 ft²)

  = (3)((112.5 ft² +136.4 ft²) = 3(248.9 ft²) = 746.7 ft²

The total area of the decks on the 3 homes is 746.7 ft².

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The resultant force is directed along the positive x axis and has a magnitude of 1330 N.
Andrew [12]

Answer:

the magnitude of F_A is 752 N

the direction theta of F_A is 57.9°

Explanations:

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Resultant force = 1330 N in x direction

∑Fx = R

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FB = 800 N

FAsin∅ + FBcos30 = 1330 N

FAsin∅ = 1330 - (800 × cos30)

FA = 637.18 / sin∅

Now ∑Fx = 0

FAcos∅ - FBsin30 = 0

we substitute for FA

(637.18 / sin∅)cos∅ = 800 × sin30

637.18 / 800 × sin30 = sin∅/cos∅

and we know that { sin∅/cos∅ = tan∅)

so tan∅ = 1.59295

∅ = 57.88° ≈ 57.9°

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FA = 637.18 / sin∅

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FA = 752 N

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