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AlekseyPX
3 years ago
13

Microwaves and infrared waves are similar because they both have

Physics
1 answer:
Orlov [11]3 years ago
3 0
Microwave and Infrared Radiation. Both are forms of electromagnetic radiation. Both are transmitted as waves. Waves are converted to heat.
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A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11-
Aleks04 [339]

Answer:

a=2.4\ m/s^2

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2

So, the acceleration of the car is 2.4\ m/s^2.

7 0
3 years ago
If the units of your answer are kg ∙ m2/s3, which of the following types of quantities could your answer be?
kirza4 [7]

Answer:

  D.  power

Explanation:

  kg represents mass

  (m/v)² represents velocity squared

Then kg·m²/s² represents mass·velocity² = <em>kinetic energy</em> or <em>potential energy</em> or <em>work</em>.

  kg·m²/s³ will be the <em>rate of doing work</em>, which is power

4 0
3 years ago
Read 2 more answers
Does gravity affect your weight???
Degger [83]
Weight is a force caused by gravity. The weight of an object is the gravitational force between the object and the Earth. The more mass the object has the greater its weight will be.
5 0
3 years ago
Read 2 more answers
An intravenous (IV) system is supplying saline solution to a patient at the rate of 0.06 cm3/s through a needle of radius 0.2 mm
horsena [70]

Answer:

Pressure applied to the needle is 7528 Pa

Explanation:

As we know by poiseuille's law of flow of liquid through a cylindrical pipe

the rate of flow through the pipe is given as

Q = \frac{\Delta P \pi r^4}{8\eta L}

now we know that

Q = 0.06 \times 10^{-6} m^3/s

radius = 0.2 mm

Length = 6.32 cm

\eta = 1\times 10^{-3} Pa s

now we have

6 \times 10^{-8} = \frac{\Delta P \pi (0.2 \times 10^{-3})^4}{8(1 \times 10^{-3})6.32 \times 10^{-2}}

3.03 \times 10^{-11} = \Delta P 5.02 \times 10^{-15}

\Delta P = 6028 Pa

now we have

P - 1500 = 6028 Pa

P = 7528 Pa

8 0
3 years ago
Determine the equivalent capacitance between points a and <br> b.
Solnce55 [7]
Where is the figure ?
7 0
3 years ago
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