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ryzh [129]
2 years ago
11

What is the difference between the law of conservation of energy and conserving energy

Physics
1 answer:
babymother [125]2 years ago
6 0
<span>law of conservation of </span>energy<span> is </span><span><span>states that energy of the universe remains constant cant be created nor destroyed and conserving energy is not using as much power as you was like trying to make power bill lower while law of conservation is constant </span> </span>


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PLEASE HELP MEEE!!!
IRINA_888 [86]

Answer:

Option C

Explanation:

Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom,  therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!

4 0
3 years ago
Discuss one way in which global warming aggravates the effect of radiation​
alukav5142 [94]
The energy that then radiates out from the surface, longwave radiation, is trapped by the same greenhouse gases, warming the air, oceans, and land. This process, appropriately dubbed “the greenhouse effect,” is how global warming occurs.
3 0
3 years ago
A sensational 130 kg midfielder has 695 J of
antoniya [11.8K]

Answer:

v = 3.27 m/s

Explanation:

KE = 1/2 mv^2

695 J = 1/2 (130kg)(v^2)

695 J / (1/2 x 130kg) = v^2

v^2 = square root of 10.69

v = 3.27 m/s

4 0
3 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 27 ft/s. Its height
Ahat [919]

Answer:

V_{3.01}=-93.2m/s

V_{3.005}=-93.1m/s

V_{3.002}=-93.04m/s

V_{3.001}=-93.02m/s

V_{3}=-93m/s

Explanation:

To calculate average velocity we need the position for both instants t0 and t1.

Now we will proceed to calculate all the positions we need:

Y_{3}=-99m/s

Y_{3.01}=-99.932m/s

Y_{3.005}=-99.4655m/s

Y_{3.002}=-99.18608m/s

Y_{3.001}=-99.09302m/s

Replacing these values into the formula for average velocity:

V_{3-3.01}=\frac{Y_{3.01}-Y_{3}}{3.01-3}=-93.2m/s

V_{3-3.005}=\frac{Y_{3.005}-Y_{3}}{3.005-3}=-93.1m/s

V_{3-3.002}=\frac{Y_{3.002}-Y_{3}}{3.005-3}=-93.04m/s

V_{3-3.001}=\frac{Y_{3.001}-Y_{3}}{3.001-3}=-93.02m/s

To know the actual velocity, we derive the position and we get:

V=27-40t = -93m/s

5 0
3 years ago
Can someone answer this form me i need help!!!
Delvig [45]
It decreased the speed
8 0
3 years ago
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