Answer:
<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>
- <u><em>Initial velocity = 33 m/s</em></u>
- <u><em>Final velocity = 0 m/s</em></u>
- <u><em>Average velocity = (33 + 0) / 2 m/s = 16.5 m/s</em></u>
Explanation:
- <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
- <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
- <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>
Answer:
The current through the resistor is 0.5 A
Explanation:
Given;
power of the light bulb = 60 W
voltage in the wall outlet across the plug terminals = 120 V
power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.
power = voltage x current
![Current = \frac{power}{voltage} = \frac{60}{120} = 0.5 A](https://tex.z-dn.net/?f=Current%20%3D%20%5Cfrac%7Bpower%7D%7Bvoltage%7D%20%3D%20%5Cfrac%7B60%7D%7B120%7D%20%3D%200.5%20A)
Therefore, for a 60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A
Answer:
![f_e = 1.51 cm](https://tex.z-dn.net/?f=f_e%20%3D%201.51%20cm%20)
Explanation:
given.
magnification(m) = 400 x
focal length (f_0)= 0.6 cm
distance between eyepiece and lens (L)= 16 cm
Near point (N) = 25 cm
focal length of the eyepiece (f_e)= ?
using equation
![m = -\dfrac{L-f_e}{f_o}.\dfrac{N}{f_e}](https://tex.z-dn.net/?f=m%20%3D%20-%5Cdfrac%7BL-f_e%7D%7Bf_o%7D.%5Cdfrac%7BN%7D%7Bf_e%7D)
![400 = \dfrac{16-f_e}{0.6}.\dfrac{25}{f_e}](https://tex.z-dn.net/?f=400%20%3D%20%5Cdfrac%7B16-f_e%7D%7B0.6%7D.%5Cdfrac%7B25%7D%7Bf_e%7D)
![9.6 = \dfrac{16-f_e}{f_e}](https://tex.z-dn.net/?f=9.6%20%3D%20%5Cdfrac%7B16-f_e%7D%7Bf_e%7D)
![9.6f_e = 16-f_e](https://tex.z-dn.net/?f=9.6f_e%20%3D%2016-f_e)
![f_e = 1.51 cm](https://tex.z-dn.net/?f=f_e%20%3D%201.51%20cm%20)
Answer:
The answer is D. right atrium, left atrium, right ventricle, left ventricle
Explanation:
The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle.The right ventricle pumps the oxygen-poor blood to the lungs.The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle.The left ventricle pumps the oxygen-rich blood to the body.
Answer:
![a=0.6\ m/s^2](https://tex.z-dn.net/?f=a%3D0.6%5C%20m%2Fs%5E2)
Explanation:
The attached figure shows the whole description. Considering the applied force is 100 N.
The acceleration of both blocks A and B, ![a=0.8\ m/s^2](https://tex.z-dn.net/?f=a%3D0.8%5C%20m%2Fs%5E2)
Firstly calculating the mass m using the second law of motion as :
F = ma
m is the mass
![m=\dfrac{F}{a}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7BF%7D%7Ba%7D)
![m=\dfrac{100\ N}{0.8\ m/s^2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B100%5C%20N%7D%7B0.8%5C%20m%2Fs%5E2%7D)
m = 125 kg
It suddenly encounters a surface that supplies 25.0 N a friction, F' = 25 N
![(F-F')=ma](https://tex.z-dn.net/?f=%28F-F%27%29%3Dma)
![(100-25)=125\times a](https://tex.z-dn.net/?f=%28100-25%29%3D125%5Ctimes%20a)
![a=\dfrac{75}{125}=0.6\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B75%7D%7B125%7D%3D0.6%5C%20m%2Fs%5E2)
So, the new acceleration of the block is
. Hence, this is the required solution.