We calculate the coordinates at t₁ = 9 min and t₂ = 10 min, since the 10th minute is between t₁ and t₂.
As it leaves from rest, it means that the initial speed is zero
t₁=9 min=540 s
t₂=10 min=600 s
x₁=at₁²/2=8*540²/2=4*291600=1166400 m
x₂=at₂²/2=8*600²/2=4*360000=1440000 m
Δx=x₂-x₁=1440000-1166400=273600 m represents the distance traveled by the car in the 10th minute of travel
when an object is revolving in circular path then its velocity is always along the tangent of the circular path
so while moving in circular path if the string is break then due to law of inertia the object will always move in the direction of initial motion
As we know that as per law of inertia if an object will not change its state of motion or state of rest until some external force will act on it.
So here also the object will move along its tangential direction once the string will break
so here the correct path will be
Option B
Answer:
potential energy which later on gets converted to kinetic energy of an object
Answer:
E = 1/2 m v^2 = 1/2 k x^2 equating KE of coyote and spring
x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m
x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2
x = 3.16 m
