The most effective way to clean a science desks is to use a soapy water solution to clean tables using a clean disposable paper towel. Second, after cleaning the table surface with soap or detergent and rinsing with water, disinfect tables by using a diluted bleach water solution
Answer: Conductor
Explanation: Because they do
Well its C, cant show you the work its in my head sorry.
Answer:
The ratio of the orbital time periods of A and B is 
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:

where
R = Radius of the orbit
Now,
For satellite A:

Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):

Answer:
-8.04 m/s2
Explanation:
To find the answer to this, you have to use the 4th kinematic equation:

You plug into the equation to get:

solve for a to get
-8.04 m/s2