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timofeeve [1]
2 years ago
5

Solve the following numerical problems​

Physics
1 answer:
Eddi Din [679]2 years ago
5 0

Answer:

See below

Explanation:

To change C to F°

  F = 9/5 C   + 32

     = 9/5 ( 45) + 32 =<u> 113° F</u>

To change F to C°   <= you could use the same equation...or re-earrange to:

C = 5/9 (F-32)

   = 5/9 ( 98.6 - 32) = 37° C

Similarly

100 C =<u> 212 ° F</u>

 to change C °  to  K    add 273.15   =  <u>373.15 K    </u>

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Answer:

Check the explanation

Explanation:

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4 0
3 years ago
Dense water near the poles sinks, creating a current towards the equator. What would you expect to happen to this current if tem
Rudik [331]
It's not c or d :/!!!!!
3 0
3 years ago
Which statements describe features that maps and globes share? Check all that apply.
leonid [27]

Maps and Globes share the following features:

Both are scale Models.

Explanation:

A globe is a scale model of the Earth that presents the most accurate depiction of geographic information such as area, distance, and direction.

A map is a two dimensional representation or a drawing of the earth’s surface, or a part of it, on a flat surface, according to a scale. Thus it is also a scale model.

A globe differs from a map. It is a three dimensional sphere representing the whole Earth.

A map is usually used to represent a specific part of the Earth and is used for Navigation. It has details and symbols. However, a globe can not be used for such details.

A globe can be used to get a broad-level picture of the world.

Keywords: geography, earth, maps, globes

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4 0
3 years ago
A thermodynamic system undergoes a process in which its internal energy decreases by 1,477 J. If at the same time 678 J of therm
Andrews [41]

Answer:2155 J

Explanation:

Given

Change in Internal energy \Delta U=-1477 J i.e. decrease in Internal Energy

Heat added to system Q=678 J

According First law for a system

dQ=dU+dW

678=-1477+dW

dW=2155 J

Thus 2155 J of work is done by system                      

5 0
3 years ago
A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When
natita [175]

Answer:

a) \mu_{k} = 0.704, b) R = 0.312\,m

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s

\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}

\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}

\mu_{k} = 0.704

b) The speed of the block is determined by using the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}

v = x\cdot \sqrt{\frac{k}{m} }

v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }

v \approx 9.829\,\frac{m}{s}

The radius of the circular loop is:

\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}

\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}

R = 0.312\,m

5 0
3 years ago
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