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3 years ago

Help with a length problem

Physics

2 answers:

Andru [333]3 years ago

6 0

It would be B

Explanation:
Because if you're not measuring in inches you want to go the next one down other than inches which would be millimeters!(: hope this helps.

Nat2105 [25]3 years ago

5 0

Answer:

B. Millimeters

Explanation:

Milliliters is a unit for volume

Millimeters are length, so its suitable for this.

Kilometers is also a unit used for length but its too big for a shoe measurement.

Kilograms is a unit for weight.

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Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a

Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2 (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0

3 years ago

Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ

Oksi-84 [34.3K]

Answer:

The number is $Z = 216 \ fringes$

Explanation:

From the question we are told that

The wavelength is $\lambda = 520 \ nm = 520 *10^{-9} \ m$

The length of the glass plates is $y = 21.1cm = 0.211 \ m$

The distance between the plates (radius of wire ) = $d = 0.028 mm = 2.8 *10^{-5} \ m$

Generally the condition for constructive interference in a film is mathematically represented as

$2 * t = [m + \frac{1}{2} ]\lambda$

Where t is the thickness of the separation between the glass i.e

t = 0 at the edge where the glasses are touching each other and

t = 2d at the edge where the glasses are separated by the wire

m is the order of the fringe it starts from 0, 1 , 2 ...

$2 * 2 * d = [m + \frac{1}{2} ] 520 *10^{-9}$

=> $2 * 2 * (2.8 *10^{-5}) = [m + \frac{1}{2} ] 520 *10^{-9}$

$m = 215$

given that we start counting m from zero

it means that the number of bright fringes that would appear is

$Z = m + 1$

=> $Z = 215 +1$

=> $Z = 216 \ fringes$

3 0

3 years ago

A car uses 2500 joules in 25 seconds. find power

irina1246 [14]

Answer:

100 W

Explanation:

The power can be defined as energy change / time taken

Energy used/time taken

So in this case you get,

Power = 2500/25 = 100 W

7 0

3 years ago

Read 2 more answers

2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after

sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

$A(t)=A_oe^{\frac{-bt}{2m}}$

or amplitude for unforce oscillation

$\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}$

$\frac{6bt}{2m}=1$

$b=\frac{m}{3T}$

Now, provided in the question Amplitude of the driven oscillation

$A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}$

the value of the maximum amplitude is obtained $(k=m\omega_d^2)$

thus,

$A=\frac{F_{max}}{(b\omega_d}$

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

$0.075=\frac{nF}{((\frac{m}{3T})2\pi}$

n = 1810

hence, there were 1810 people on the bridge

b) $A=\frac{F_{max}}{(b\omega_d}$

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

$A=\frac{F_{max}}{(3b\omega_d}$

$A=\frac{1}{(3}A_o$

$A=\frac{1}{(3}0.075$

A = 0.025 m = 25 mm

6 0

3 years ago

force between two identical short bar magnets whose centres are part is 4.8 N when their axes are in same line. if this separati

77julia77 [94]

There uyou go. hope this helps.

5 0

3 years ago