Let the bigger sphere be sphere 1 and the let the smaller sphere be sphere 2. Rest of the answer is in the picture.
Help with a length problem
2 answers:
You might be interested in
A) diagram is shown on the image below
b) Mass m = 450/9.8 = 45.918 KgNet upward force = T + T = 2T = 620 NNet downward force = 290 + 160 = 450 NResultant force F = Net upward force - Net downward force ma = 620 - 450 45.918 a = 170 Acceleration a = 170/45.918 = 3.7 m/s^2 (upward)Here Net upward force > Net downward force, So the resultant force directed upwards, hence acceleration will be upward.
(c)Consider the case of boy alone, then from Newtons law of motion we can write Net force F = n + T - 290 ma = n + 310 - 290 where m = 290/9.8 = 29.59 Kg 29.59 * 3.7 = n + 20 109.483 = n + 20 n = 89.483 N
b) Mass m = 450/9.8 = 45.918 KgNet upward force = T + T = 2T = 620 NNet downward force = 290 + 160 = 450 NResultant force F = Net upward force - Net downward force ma = 620 - 450 45.918 a = 170 Acceleration a = 170/45.918 = 3.7 m/s^2 (upward)Here Net upward force > Net downward force, So the resultant force directed upwards, hence acceleration will be upward.
(c)Consider the case of boy alone, then from Newtons law of motion we can write Net force F = n + T - 290 ma = n + 310 - 290 where m = 290/9.8 = 29.59 Kg 29.59 * 3.7 = n + 20 109.483 = n + 20 n = 89.483 N