1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
4 years ago
8

How would one know if something is an element?

Chemistry
2 answers:
tankabanditka [31]4 years ago
7 0
An element is a substance made from only 1 type of atom. It is a pure substance and they are the building blocks for the rest of matter in the world.
hichkok12 [17]4 years ago
6 0
You would be able to tell if you could see it on the period table ig.
You might be interested in
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
What Happens When Stress builds faults? O Energy is Absorbed O Rock can bend and break O Plates form on the lithosphere O Earthq
Bumek [7]
It decease during time period
8 0
3 years ago
Read 2 more answers
How do I write 0.03438 m in scientific notation using 3 digits?
Law Incorporation [45]
3.44x10^2
you move the decimal over to get a single digit number with change. The number of times you move the decimal is the number for the 10 power
4 0
3 years ago
1.) Which line is pointing to the axon terminals?
Naily [24]

Answer:

1.) 5 or D

2.) 2 or B

3.) 4 or D

4.) 1 or A

Explanation:

I got them correct on the quiz on edge

4 0
2 years ago
Energy from the Sun reaches Earth through
g100num [7]

Solar Radiation(Basically Radiation)

8 0
3 years ago
Read 2 more answers
Other questions:
  • If the internal energy of the products of a reaction is lower than the internal energy of the reactants, what is the sign of δe
    11·1 answer
  • The four tastes are:<br> bitter<br> sour<br> fishy<br> salty<br> fruity<br> sweet
    8·1 answer
  • Which of the following is a mixture?<br><br> steel<br> water<br> oxygen<br> gold
    9·2 answers
  • What is molarity of a solution containing 0.34 moles of FeCl3 in the 0.45 liters of water
    10·1 answer
  • How many grams are there in 457.25 pounds?
    15·2 answers
  • What causes a star to shine brightly
    6·1 answer
  • Lead (Pb) is used to make a number of different alloys. What is the mass of lead present in an alloy containing 0.15 mol of lead
    7·1 answer
  • Calculate the pH of a 0.0150 M HNO3 solution. Assume HNO3
    9·1 answer
  • The colourless coating on a photographic film contains a chemical substance which reacts upon exposure to light, causing the fil
    5·1 answer
  • 10.Using the below valency chart, write chemical formula for aluminum oxide and
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!