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Mandarinka [93]
3 years ago
15

If a car passes a pedestrian, a change in pitch is __________.

Chemistry
2 answers:
enot [183]3 years ago
6 0
Given two questions:

<span>1) If a car passes a pedestrian, a change in pitch is ______________. 
The answer is the change in pitch is perceived by the pedestrian since he is the one in a relatively constant position compared to the car passing. 

2) </span><span>In the Doppler Effect lab, which statement best describes what you demonstrated about speed and pitch?

The answer is 'speed and direction affect pitch'.</span>
marusya05 [52]3 years ago
4 0

The correct answers are as follows:

1. If a car passes a pedestrian, a change in pitch is PERCEIVED BY THE PEDESTRIAN.

The pitch of a sound refers to the quality of sound that makes it to be rated as a low or a high sound. Pitch varies with distance, that is, as one moves closer to a source of sound, the sound pitch increases and as one move away from the source of a sound, the pitch of the sound decreases. In the question given above, a change in pitch of the car sound will be perceived by the pedestrian, this is because, his position is constant relevant to that of the passing car. As the car moves away the sound pitch will decreases.

2. The correct answer is this: SPEED AND DIRECTION AFFECT PITCH.

Doppler effects refers to the increase or decrease in the pitch of a sound as one move towards or away from a sound. This change in sound is due to changes in the frequency of the sound. Speed and direction are two factors that affect the pitch of a sound.

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A first-order reaction is 81omplete in 264s. A. What is the half-life for this reaction? b. How long will it take for the reacti
Arlecino [84]

A first-order reaction is 81omplete in 264s.The half-life for this reaction (i) t 1/2 = =3.465×10 −3 s.to reach 95% Completion = 285 s.

To measure reaction rates, chemists initiate the reaction, measure the concentration of the reactant or product at different times as the reaction progresses,

For a 0-order response, the mathematical expression that may be employed to determine the half of life is: t1/2 = [R]0/2k. For a first-order reaction, the half of-existence is given by: t1/2 = zero.693/ok. For a 2d-order response, the method for the half-life of the response is: 1/okay[R]0

The 1/2-life of a response (t1/2), is the quantity of time needed for a reactant concentration to lower via half of compared to its initial awareness. Its software is used in chemistry and medicine to are expecting the awareness of a substance over time

Half of the lifestyles is the time required for exactly 1/2 of the entities to decay   50%.

Learn more about first order reaction here:-

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5 0
2 years ago
Please help!!!!
Tomtit [17]

Answer 1) Option D : Discrete


Explanation : As in the example the scientist studies about the effects of growing human populations on the biodiversity which is found in a region, and where each region was selected had a different population density of humans from 1 to 10 million per 10 square miles. Then in each region the number of different species that can be found was recorded. So here the numerical data was collected for different regions. So, we can conclude it as discrete because when the variable takes on a countable number of values it is called as discrete.


Answer 2) Option D : The entertainment industry


Explanation : When people had enough time and money with them there was no need of creating the communications industry as it was a need not a luxurious thing. With the creation of Internet industry it is somewhat irrelevant. They had enough of time and money so building a labor industry seems to be a lame choice. So, the option of entertainment industry suits the best.

6 0
3 years ago
Read 2 more answers
A strong acid can also be described as a very weak .
faltersainse [42]
I guess is weak alkaline. when the substance is more acidic, there will be less alkalinity
4 0
3 years ago
When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to
Reika [66]

Answer:

2

0.4167\ \text{M}^{-1}\text{min}^{-1}

Explanation:

Half-life

{t_{1/2}}A=2\ \text{min}

{t_{1/2}}B=4\ \text{min}

Concentration

{[A]_0}_A=1.2\ \text{M}

{[A]_0}_B=0.6\ \text{M}

We have the relation

t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}

So

\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}

Comparing the exponents we get

1=n-1\\\Rightarrow n=2

The order of the reaction is 2.

t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}

The rate constant is 0.4167\ \text{M}^{-1}\text{min}^{-1}

3 0
3 years ago
What are metals that have been mixed together called
d1i1m1o1n [39]

Answer:

Alloys

I hope this helps!

6 0
3 years ago
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