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Mandarinka [93]
3 years ago
15

If a car passes a pedestrian, a change in pitch is __________.

Chemistry
2 answers:
enot [183]3 years ago
6 0
Given two questions:

<span>1) If a car passes a pedestrian, a change in pitch is ______________. 
The answer is the change in pitch is perceived by the pedestrian since he is the one in a relatively constant position compared to the car passing. 

2) </span><span>In the Doppler Effect lab, which statement best describes what you demonstrated about speed and pitch?

The answer is 'speed and direction affect pitch'.</span>
marusya05 [52]3 years ago
4 0

The correct answers are as follows:

1. If a car passes a pedestrian, a change in pitch is PERCEIVED BY THE PEDESTRIAN.

The pitch of a sound refers to the quality of sound that makes it to be rated as a low or a high sound. Pitch varies with distance, that is, as one moves closer to a source of sound, the sound pitch increases and as one move away from the source of a sound, the pitch of the sound decreases. In the question given above, a change in pitch of the car sound will be perceived by the pedestrian, this is because, his position is constant relevant to that of the passing car. As the car moves away the sound pitch will decreases.

2. The correct answer is this: SPEED AND DIRECTION AFFECT PITCH.

Doppler effects refers to the increase or decrease in the pitch of a sound as one move towards or away from a sound. This change in sound is due to changes in the frequency of the sound. Speed and direction are two factors that affect the pitch of a sound.

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Which law is associated with inertia? *
defon

Newton first law of motion

Explanation:

This law by Newton states that an object will remain at rest, or a moving object will stay in motion in a straight line and with the same speed unless an external and unbalanced force acts on the object.

One application of this Newtonian law is in the launching of projectiles like ballistic missiles.  A ballistic missile parabolic path is affected by its inertia and the unbalanced forces acting on the object such as air resistance/ drag and gravity.

4 0
3 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
PLEASE HELP When I combine Sprite with a sour candy, it starts to bubble a lot. Is this a physical or chemical change?
maksim [4K]

Answer:

B. chemical

Explanation:

Chemical change cannot go back to its original form

4 0
2 years ago
Read 2 more answers
Beryllium oxide, Beo, is an electrical insulator. How
egoroff_w [7]

Answer:

There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.

Explanation:

We can calculate the number of moles (η) of BeO as follows:

\eta = \frac{m}{M}

Where:

m: is the mass = 250 g

M: is the molar mass = 25.0116 g/mol

Hence, the number of moles is:

\eta = \frac{250 g}{25.0116 g/mol} = 10.0 moles

Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.  

I hope it helps you!

3 0
3 years ago
Suppose you wanted to make a buffer of exactly ph 7.00 using kh2po4 and na2hpo4. if the final solution was 0.10 m in kh2po4, wha
OleMash [197]

Answer:- 0.138 M

Solution:- The buffer pH is calculated using Handerson equation:

pH=pKa+log(\frac{base}{acid})

KH_2PO_4 acts as a weak acid and Na_2HPO_4 as a base which is pretty conjugate base of the weak acid we have.

The acid hase two protons(hydrogen) where as the base has only one proton. So, we could write the equation as:

H_2PO_4^-\rightleftharpoons H^++HPO_4^-^2

Phosphoric acid gives protons in three steps. So, the above equation is the second step as the acid has only two protons and the base has one proton.

So, we will use the second pKa value. The acid concentration is given as 0.10 M and we are asked to calculate the concentration of the base to make a buffer of exactly pH 7.00.

Let's plug in the values in the equation:

7.00=6.86+log(\frac{base}{0.10})

7.00-6.86=log(\frac{base}{0.10})

0.14=log(\frac{base}{0.10})

Taking antilog:

10^0^.^1^4=\frac{base}{0.10}

1.38=\frac{base}{0.10}

On cross multiply:

[base] = 1.38(0.10)

[base] = 0.138

So, the concentration of the base that is Na_2HPO_4 required to make the buffer is 0.138M.

5 0
3 years ago
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