The given compound 3-chloro-2,2,5-trimethylhexane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here the chiral carbon has 4 distinct groups such as : chlorine , hydrogen , 2-methylpropyl , tertbutyl .
<h3>What is di-symmetry?</h3>
Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>
Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>
Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg
Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
