Boyle's Law
Pressure 1 × Volume 1 = Pressure 2 × Volume2
or P1×V1= P2×V2
Finding Volume 2
(5.75atm)(5.14L) = (2.49atm)(V2)
Then Multiply
29.55atm•L = 2.49atm(V2)
Divided by 2.49
29.56atm•L / 2.49atm = 2.49atm(V2) / 2.49atm
V2= 11.87 L
Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
I believe the answer is C
Answer: They are close to each other by 41.03 m^3
Explanation:
From Ideal gas equation, PV = nRT
Where n is negligible
R is gas constant = 8.314 J/mol.k
T = 30 + 273 = 303K
P = 1.02 * 103351.5 = 103351.5 Pascal
Then;
PV = RT
V = P/RT
V = 103351.5/(8.314*303)
V = 41.03m^3
