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3 years ago

What is the symbol, atomic number, atomic mass, # of protons, # of neutrons, # of electrons, ion charge for the beryllium ion?

Chemistry

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

Symbol Be

atomic number 4

protons 4

neutrons 5

electrons 4

ion charge +2

Explanation:

Look at the periodic table and all the answers can be found there. If you would like to learn how to find them please message me below.

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A sample of argon gas has a volume of 73 mL at a pressure of 1.20 atm and a temperature of 112 degrees Celsius. What is the fina

NeX [460]

Answer:

V₂ → 106.6 mL

Explanation:

We apply the Ideal Gases Law to solve the problem. For the two situations:

P . V = n . R . T

Moles are still the same so → P. V / R. T = n

As R is a constant, the formula to solve this is: P . V / T

P₁ . V₁ / T₁ = P₂ .V₂ / T₂ Let's replace data:

(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C

((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂

58.66 mL.atm = 0.55 atm . V₂

58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL

3 0

3 years ago

When the energy is removed what will happen to a gas?

creativ13 [48]

Answer:

Hey mate 
I hope it helps

Explanation:

<h3>Removing Energy: Removing energy will cause the particles in a liquid to begin locking into place. A. Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.</h3>

<h2>PLZ MARK ME AS BRAIN LIST </h2>

THANKS 

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME ASAP!

uranmaximum [27]

your answer is b hope this helps

7 0

3 years ago

Read 2 more answers

the amount of solar energy reaching 1 m² of earths surface each second is 1.366 x 10^3 joules. if this energy was converted into

Advocard [28]

I think is 6.588579795x10^13 Kg because the equation is E=mc^2 and E is your Joules and c^2= 9x10^16 so m=(c^2)/E

4 0

3 years ago

Nitrogen has an average atomic mass of 14.00674. it has two isotopes, n-14 and n-15, with atomic masses of 14.0031 amu and 15.00

masya89 [10]

In this case, we are going to assume that there are 100 atoms to make things easier.

Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%

14.0031*(100-R)% + 15.001 * R%= 14.00674
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %

14.0031*(100-R) + 15.001 * R= 14.00674
1400.31-14.0031R+15.001R=1400.674
0.9979R=0.364
R=0.3648

Then, the abundance of n-15 is 0.3648%

5 0

2 years ago