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DochEvi [55]
3 years ago
15

Seven wholes times 2 fifteenths

Mathematics
1 answer:
Margarita [4]3 years ago
4 0
7 x 2/15

7 x 2 = 14

14/15 is your answer

hope this helps 
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Find the x intercept of the line graphed by the equation 1/2x-7y=7
Rina8888 [55]

Answer:

1/2*x - 7y = 7

1/2*x - 7 = 7y

1/14*x - 1 = y

y = 1/14*x - 1

3 0
3 years ago
PLZZ HELP I NEED AN EXPERT ANSWER
Sav [38]
The equation of a line is y = mx + b


We know there is a b because the y intercept is not zero, so the first choice is wrong. We also know the last choice is wrong because this problem definitely has a slope (m).


The slope of the line of best fit seems to be closest to 3.25, meaning it goes up about that much for every one unit it goes to the right.


The second choice is correct.
6 0
3 years ago
When factoring, what should be the greatest common factor of the terms left inside the parenthesis?
skad [1K]

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2

Step-by-step explanation:

3 0
3 years ago
To solve the inequality 4x < 8, you would divide both sides of the inequality by 4.
KiRa [710]

Answer:

True

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4 0
3 years ago
Two coworkers commute from the same building. They are interested in whether or not there is any variation in the time it takes
jenyasd209 [6]

Answer:

Step-by-step explanation:

Hello!

You have two samples.

Sample 1 (time that takes one commute of worker 1)

n₁= 20

S₁²= 12.2

Sample 2 (time that takes one commute of worker 2)

n₂= 20

S₂²= 16.9

The hypothesis is that the first coworker is more consistent with his commute times, this means that the variability of his commute times is less than the variability of the commute times of worker 2. With this in mind, the hypothesis for a variance ratio test is:

H₀: σ₁² ≥ σ₂²

H₁:: σ₁² < σ₂²

α: 0.10

The statistic for this test is:

F= (S₁²/S₂²) * (σ₁²/σ₂²) ~ F_{n1-1;n2-1}

The test is one-tailed (left) with just one critical value:

F_{n_1-1;n_2-1;\alpha } = \frac{1}{F_{n_2-1;n_1-1;1-\alpha }} = \frac{1}{F_{19;19;0.90}} = \frac{1}{1.82} =0.549

(The F-table I use only has the values for high probabilities so I've used a conversion method to obtain the value for the small probability)

Your decision rule is:

If F ≤ 0.549, you reject the null hypothesis.

if F > 0.549, you support the null hypothesis.

The calculated value:

F= (S₁²/S₂²) * (σ₁²/σ₂²) = (12.2/16.9) * 1= 0.722

Since the calculated F-value is greater than the critical value, the decision is to not reject the null hypothesis. So you can say that the variability of the commute times of worker 1 is less than the variability of the commute times of worker 2.

I hope you have a SUPER day!

7 0
3 years ago
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