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Wewaii [24]
3 years ago
9

A 14-year-old girl sprained her ankle. She rates her pain 5/10. On examination, she has moderate tenderness and swelling with de

creased range of motion secondary to pain. Although quite painful, she is able to ambulate. What is the grade of this ankle sprain
Biology
1 answer:
pochemuha3 years ago
5 0

Answer:

Grade II

Explanation:

  • When there is either a partial or complete tearing on ligaments that are responsible for supporting the joint of the ankle then it causes an ankle sprain.
  • Based on the exam findings as well as the loss in functionality of the ankle, an ankle sprain can be categorized as grade I, II or III.
  • In the given situation the 14-year-old girl has a grade II ankle sprain which is characterized by an incomplete tear of the ligaments along with moderate pain (as she rates it 5/10), moderate tenderness, loss of range of some functions, and swelling.
  • All of the characteristics of the sprain resemble those of the grade II ankle sprain tear and hence, it is characterized as a grade II ankle sprain.
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1) RNA strand =  <em>UCA  GCA  AAU</em>

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Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named <em>anticodon</em><em>.</em> The other site couples with an amino acid through the action of the aminoacyl-tRNA synthase enzyme. The whole complex, amino acid + enzyme + tRNA is named aminoacyl-tRNA. Considering that there are twenty amino acids available, there are also twenty complexes of aminoacyl-tRNA, one for each amino acid.  

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Now, to fill in the boxes, you need to pay attention to two things:

• <u>Anticodon</u>: In this box, you need to place the sequence of bases that pairs with the mRNA codon.  

• <u>Amino Acid</u>: In this box, you need to place the amino acid that is codified by the<u> mRNA </u>codon.  

For instance, let us say that the codon of mRNA is CUC. The anticodon for this sequence is GAG (because guanine joins cytosine and adenine joins uracyl).  

The amino acid places on the 3´extreme of the tRNA molecule will be the one that is codified by the codon, NOT the anticodon. So, as the codon is CUC, the amino acid will be Leucine, Leu. Do not use the anticodon GAG to fill these boxes. Remember that tRNA is translating information carried by the mRNA, so we need to use this information to grow the protein.

<em />

1)

Strand of DNI  →  AGT  CGT  TTA

  • Each of these letters are bases → Adenine, A - Guanine, G - Thymine, T - Cytocine, C
  • Each of these three-lettered groups are codons.

So, we need to pair these bases, knowing that:

Adenine (A) and guanine (G) derive from purines, while Thymine (T) Uracile (U), and Cytosine (C) derive from Pyrimidines.  

In the DNA molecule, Adenine (Purine) always pairs with Timine (Pyrimidine), while Guanine (Purin) forms pairs with Cytosine.

In the RNA molecule,<em> Adenine is paired with Uracil, U. </em>So, whenever there is an Adenine in the DNI strand, it pairs with Uracil of RNA strand. If there is a Thymine in the DNI strand, it pairs Adenine of the RNA strand. And, as always, Guanine pairs with Cytosine.

  • A ⇒ U
  • T ⇒ A
  • G ⇔ C

Knowing how to pair bases, we can fill the RNA molecule boxes.

  • Strand of DNI  →  AGT                   CGT              TTA
  • <em>Strand of RNA →  UCA                  GCA              AAU</em>

<em>                                      A ⇒ U              C ⇒ G            T ⇒ A</em>

<em>                                     G ⇒ C               G ⇒ C            T ⇒ A</em>

<em>                                     T ⇒ A                T ⇒ A            A ⇒ U</em>

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<em>To fill the boxes you should have a genetic code chart to see the codons that codify for each amino acid. </em>

Codon:                 AAU                 CGA                UAG

Amino acids:   Asparagine       Arginine             Stop

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