A taste sensation that is triggered by the amino acid glutamate is known as

White vitriol molecular formula and green vitriol molecular formula??

IgorC [24]

Answer:

Green vitriol- FeSO4·7H2O

white vitriol- ZnSO₄

8 0

2 years ago

I need someone to answer these.

SCORPION-xisa [38]

Answer:

The identity of an atom is determined my the number of protons. This is the atomic number.

The particle(s) found inside the nucleus are called protons and neutrons. Their combined mass is referred to as the mass number.

Isotopes have the same number of protons, but different number of neutrons.

7 0

3 years ago

While playing soccer, Caria slides across one of the lines on the field. When she stands up, what base does she stop?

SVEN [57.7K]

Answer:

Canxi hydroxit

Explanation:

8 0

2 years ago

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A reactant decomposes with a half-life of 29.5 s when its initial concentration is 0.229 M. When the initial concentration is 0.

Dmitrij [34]

Answer :

The order of reaction is, 0 (zero order reaction).

The value of rate constant is, $0.00388Ms^{-1}$

Explanation :

Half life : It is defined as the time in which the concentration of a reactant is reduced to half of its original value.

The general expression of half-life for nth order is:

$t_{1/2}\propto \frac{1}{[A_o]^{n-1}}$

or,

$\frac{t_{1/2}_1}{t_{1/2}_2}=\frac{[A_2]^{n-1}}{[A_1]^{n-1}}$

or,

$n=\left(\frac{\log\frac{(t_{1/2})_1}{(t_{1/2})_2}}{\log\frac{(A)_2}{(A)_1}}\right )+1$ .............(1)

where,

$t_{1/2}$ = half-life of the reaction

n = order of reaction

[A] = concentration

As we are given:

Initial concentration of A = 0.229 M

Final concentration of A = 0.639 M

Initial half-life of the reaction = 29.5 s

Final half-life of the reaction = 82.3 s

Now put all the given values in the above formula 1, we get:

$n=\left (\frac{\log \frac{29.5}{82.3}}{\log\frac{0.639}{0.229}}\right )+1$

$n=0.000196\approx 0$

Thus, the order of reaction is, 0 (zero order reaction).

Now we have to determine the rate constant.

To calculate the rate constant for zero order the expression will be:

$t_{1/2}=\frac{[A_o]}{2k}$

When,

$t_{1/2}$ = 29.5 s

$[A_o]$ = 0.229 M

$29.5s=\frac{0.229M}{2k}$

$k=0.00388Ms^{-1}$

Thus, the value of rate constant is, $0.00388Ms^{-1}$

4 0

3 years ago

The chemical symbol of several elements are given below. Determine the atomic number of each element. Chemical Atomic Number Sym

spayn [35]

Explanation:

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For A:

1) Fe

The atom given to us is iron. It is present in Group 8 and period 4 of the periodic table. The atomic number of iron is 26

2) Be

The atom given to us is beryllium. It is present in Group 2 and period 2 of the periodic table. The atomic number of beryllium is 4

3) Kr

The atom given to us is krypton. It is present in Group 18 and period 4 of the periodic table. The atomic number of iron is 36

For B:

1) $_{24}^{53}\textrm{Cr}$

Atomic number = Number of protons = Number of electrons = 24

Mass number = 53

Number of neutrons = 53 - 24 = 29

The number of protons, electrons and neutrons for the given element are 24, 24 and 29 respectively

2) $_{44}^{103}\textrm{Ru}$

Atomic number = Number of protons = Number of electrons = 44

Mass number = 103

Number of neutrons = 103 - 44 = 59

The number of protons, electrons and neutrons for the given element are 44, 44 and 59 respectively

3) $_{30}^{67}\textrm{Zn}$

Atomic number = Number of protons = Number of electrons = 30

Mass number = 67

Number of neutrons = 67 - 30 = 37

The number of protons, electrons and neutrons for the given element are 30, 30 and 37 respectively

For C:

1) Atomic number = 14; Mass number = 28

The element having atomic number '14' is Silicon

The isotopic symbol of the element is $_{14}^{28}\textrm{Si}$

The symbol of the element is 'Si'

2) Atomic number = 18; Mass number = 40

The element having atomic number '18' is Argon

The isotopic symbol of the element is $_{18}^{40}\textrm{Ar}$

The symbol of the element is 'Ar'

3) Atomic number = 19; Mass number = 39

The element having atomic number '19' is Potassium

The isotopic symbol of the element is $_{19}^{39}\textrm{K}$

The symbol of the element is 'K'

5 0

3 years ago