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2 years ago

The longest wavelength within the visible spectrum is _______ light.

2 answers:

5 0

The longest wavelength within the visible spectrum is the red light. The answer is letter C. It is called visible light because it is the only light that can be seen by the human eye. Red light is the longest wavelength around 620 to 750 nanometer. It is followed by orange which has a wavelength of 590 t 620 nanometer. And then blue which has a wavelength of 450 to 495 nanometer. And the shortest wavelength is violet which has a wavelength of 380 to 459 nanometer.

Alik [6]2 years ago

5 0

Answer:

red light.

Explanation:

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Why is the current atomic model called the "electron cloud model?

a_sh-v [17]

The electron cloud model is the orbitals. Its called that because the model demonstrates the atom. The electrons are in the orbital cloud.

5 0

2 years ago

A Cannonball is shot at an angle of 35.0 degrees and is in flight for 11.0 seconds before hitting the ground at the same height

nikdorinn [45]

Answer:

Explanation:

According to Equations of Projectile motion :

$Time\ of\ Flight = \frac{2vsin(x)}{g}$

vsin(x) = 11 * 9.8 / 2 = 53.9 m/sec

(A) v (Initial velocity) = 11 * 9.8 / 2 * sin(35) = 94.56 m/sec

$Maximum Height = \frac{(vsinx)^{2} }{2g}$

(B) Maximum Height = 53.9 * 53.9 / 2 * 9.8 = 142.2 m

$Horizontal Range = vcosx * t$

(C) Horizontal Range = 94.56 * 0.81 * 11 = 842.52 m

4 0

3 years ago

A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N

Nana76 [90]

Answer:

ans: 1750 kg

Explanation:

F = ma

so ,

m = F/a

= 3500 / 2

= 1750 kg

5 0

2 years ago

What was the most serious money problem faced by people in the early United States?

alexira [117]

♥B. There was no single medium of exchange.♥
Take a look at the saying "Not worth a Continental".
It referrers to the fact that currency issued by the Continental Congress was usually just a promise to pay.
Leaving your answer with ♥B♥

5 0

2 years ago

A screen is placed 1.20m behind a single slit. The central maximum in the resulting diffraction pattern on the screen is 1.40cm

andrew11 [14]

Answer:

2.8 cm

Explanation:

$y_1$ = Separation between two first order diffraction minima = 1.4 cm

D = Distance of screen = 1.2 m

m = Order

Fringe width is given by

$\beta_1=\dfrac{y_1}{2}\\\Rightarrow \beta_1=\dfrac{1.4}{2}\\\Rightarrow \beta_1=0.7\ cm$

Fringe width is also given by

$\beta_1=\dfrac{m_1\lambda D}{d}\\\Rightarrow d=\dfrac{m_1\lambda D}{\beta_1}$

For second order

$\beta_2=\dfrac{m_2\lambda D}{d}\\\Rightarrow \beta_2=\dfrac{m_2\lambda D}{\dfrac{m_1\lambda D}{\beta_1}}\\\Rightarrow \beta_2=\dfrac{m_2}{m_1}\beta_1$

Distance between two second order minima is given by

$y_2=2\beta_2$

$\\\Rightarrow y_2=2\dfrac{m_2}{m_1}\beta_1\\\Rightarrow y_2=2\dfrac{2}{1}\times 0.7\\\Rightarrow y_2=2.8\ cm$

The distance between the two second order minima is 2.8 cm

8 0

2 years ago