Complete Question
Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail
Answer:

Explanation:
From the question we are told that:
Mass 
Initial Velocity 
Distance 
Diameter 
Length 
Generally the equation for Force is mathematically given by



Leaning against a brick wall.
All the others use scientific forces of work.
-Steel jelly.
Answer:
22.05 Kg
Explanation:
Apply the formula:
GPE = Gravity . Mass . ΔHigh
2778.3 = 10 . Mass . 12.6
2778.3 = 126 . Mass
Mass = 2778.3/126
Mass = 22.05
Answer:
Resultant force, R = 10 N
Explanation:
It is given that,
Force acting along +x direction, 
Force acting along +y direction, 
Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

Here 


R = 10 N
So, the resultant force on the object is 10 N. Hence, this is the required solution.