Step-by-step explanation:
Triangle PQR is in a coordinate plane. The triangle is reflected across the y–axis and
then translated 11 units left to form Triangle P'Q'R'. Determine which of the following statements must be true regarding this transformation. Select True or False for each statement.
Angle P has the same measure as angle P'. T or F
Angle Q has the same measure as angle R'. T or F
Angle R has the same measure as angle R'. T or F
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Answer:
Express 5 72 in simplest radical form:
Factorize the 72 in your expression:
5√72 = 5√(2*2*2*3*3)
take a pair of two's and a pair of three's out of the radical sign:
5√72 = 5*2*3√2 = 30√2
this is the simplest radical form
Step-by-step explanation:
Slope of y=1-2x is -2
Using point intercept form:
y-1=-2(x-3)
y-1=-2x+6
y=-2x+7
The volume of a rectangular prism is its length times width times height, or algebraically,

. You may be used to computing volume with numbers, but remember, a variable is a stand-in for a number. So you can solve this in the same way. Substitute

into the formula for volume. You get

, and you multiply these factors together. As you would with ordinary fractions, multiply the numerators and denominators across. You get

. It seems that the book wants you to simplify by bringing the 6 up to the denominator. Recall the rule

, if n is non-negative. The opposite applies so that

. For your final answer, you write

. This corresponds to
answer choice B.
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.