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lesya692 [45]
3 years ago
11

Question 096 Propose a three-step synthetic sequence to accomplish the transformation below. 1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2C

CNa 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa 1) NaOEt; 2) NBS, hν; 3) NaSBu

Chemistry
1 answer:
salantis [7]3 years ago
8 0

Complete Question

Question 096 Propose a three-step synthetic sequence to accomplish the transformation below.

Option 1 =>  1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2CCNa

Option 2 => 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 3 => 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa

Option 4 => 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR

Option 5 => 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 6 => 1) NaOEt; 2) NBS, hν; 3) NaSBu

Answer:

The correct option is option 5

Explanation:

   The mechanism of the reaction is shown on the first uploaded image

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Answer:

0.98 g of H₂

Explanation:

the balanced equation for the reaction is

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molar ratio of Mg to H₂ is 1:1

number of Mg moles reacted = 12 g/ 24.3 g/mol = 0.49 mol

according to molar ratio

when 1 mol of Mg reacts 1 mol of H₂ is formed

therefore when 0.49 mol of Mg reacts - 0.49 mol of H₂ forms

therefore mass of H₂ formed = 0.49 mol x 2 g/mol = 0.98 g

mass of H₂ formed is 0.98 g

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What is the pH of a solution that is 0.40 M NaBrO and 0.50 M HBrO (hypobromous acid) (Ka for HBrO = 2.3 x 10^-9)
Pie

Answer

pH=8.5414

Procedure

The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.

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