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lesya692 [45]
4 years ago
11

Question 096 Propose a three-step synthetic sequence to accomplish the transformation below. 1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2C

CNa 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa 1) NaOEt; 2) NBS, hν; 3) NaSBu

Chemistry
1 answer:
salantis [7]4 years ago
8 0

Complete Question

Question 096 Propose a three-step synthetic sequence to accomplish the transformation below.

Option 1 =>  1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2CCNa

Option 2 => 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 3 => 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa

Option 4 => 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR

Option 5 => 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 6 => 1) NaOEt; 2) NBS, hν; 3) NaSBu

Answer:

The correct option is option 5

Explanation:

   The mechanism of the reaction is shown on the first uploaded image

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Which molecular solid would have the highest melting point?
TEA [102]

Answer:

Choice B. The solid with hydrogen bonding.

Assumption: the molecules in the four choices are of similar sizes.

Explanation:

Molecules in a molecular solid are held intact with intermolecular forces. To melt the solid, it is necessary to overcome these forces. The stronger the intermolecular forces, the more energy will be required to overcome these attractions and melt the solid. That corresponds to a high melting point.

For molecules of similar sizes,

  • The strength of hydrogen bonding will be stronger than the strength of dipole-dipole attractions.
  • The strength of dipole-dipole attractions (also known as permanent dipole) will be stronger than the strength of the induced dipole attractions (also known as London Dispersion Forces.)

That is:

Strength of Hydrogen bond > Strength of Dipole-dipole attractions > Strength of Induced dipole attractions.

Accordingly,

Melting point due to Hydrogen bond > Melting point due to Dipole-dipole attractions > Melting point due to Induced Dipole attractions.

  • Induced dipole is possible between all molecules.
  • Dipole-dipole force is possible only between polar molecules.
  • Hydrogen bonds are possible only in molecules that contain \rm H atoms that are bonded directly to atoms of \rm F, \rm O, or \rm N.

As a result, induced dipoles are the only force possible between molecules of the solid in choice C. Assume that the molecules are of similar sizes, such that the strengths of induced dipole are similar for these molecules.

Melting point in choice B > Melting point in choice D > Melting point in choice A and C.

8 0
3 years ago
Seven carbon chain with CH3 attached to second and third carbon
Nikitich [7]

Answer:

2,3-dimethylheptane.

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

           |        |

       CH₃    CH₃

Explanation:

Hello there!

In this case, according to the given instructions, it is possible to draw the organic chemical structure by connecting seven carbon atoms along the parent chain with two methyl substituents at the second and third carbon atoms; thus, the resulting structure is:

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

           |        |

       CH₃    CH₃

Furthermore, the name would be 2,3-dimethylheptane according to the IUPAC rules for nomenclature.

Best regards!

6 0
3 years ago
How many grams of cl are in 445 g of cacl2?
RideAnS [48]
<span>284 g First, lookup the atomic weights of all the elements involved. Atomic weight of Calcium = 40.078 Atomic weight of Chlorine = 35.453 Now calculate the molar mass of CaCl2 40.078 + 2 * 35.453 = 110.984 Using that molar mass, calculate how many moles of CaCl2 you have. 445 g / 110.984 g/mol = 4.009586967 mol Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms. 4.009586967 * 2 = 8.019173935 And finally, multiply by the atomic weight of chlorine. 8.019173935 * 35.453 = 284.3037735 Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.</span>
7 0
4 years ago
1 point
blsea [12.9K]

Answer:

It freezes at 32 f

Explanation:

6 0
3 years ago
Mercury-203 undergoes beta minus decay. 203 80 hg → 203 81 tl ? the subatomic particle produced is a(n) . 203 80 hg → 203 81 tl
cricket20 [7]

The correct balanced equation of a beta decay undergone by Mercury-203 is as follows:

203 80 Hg → 203 81 + 0 -1 e

<h3>What is beta decay?</h3>

Beta decay in radioactivity refers to the release of a beta particle by a radioactive element.

Beta particle is characterized by the possession of mass number 0 and atomic number -1.

This means that if Mercury-203 undergoes beta decay, the atomic number of the resulting isotope will be +1 as follows:

203 80 Hg → 203 81 Tl + 0 -1 e

Learn more about beta radiation at: brainly.com/question/1580990

8 0
2 years ago
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