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expeople1 [14]
3 years ago
8

Examples of two substances being mixed and the ​

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

ocean water liquid and steel solid

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How many moles of CF4 can be produced when 8.95 mol C reacts with 7.88 mol F2?
Molodets [167]

The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.

<h3>Reaction between Carbon and Fluorine </h3>

The reaction between carbon and Fluorine is given as;

C + 2F₂  -------> CF₄

1  :    2                1

from the reaction above,

2 moles of F₂ requires 1 mole of C

7.88 mole of  F₂ will require:    7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.

The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.

Learn more about moles here: brainly.com/question/15356425

#SPJ1

8 0
2 years ago
Which of the following is the BEST description of a temperate grassland ecosystem?
Likurg_2 [28]

Answer:

It is an area that is covered in grasses and wildflowers that receives enough rainfall to support the grassland but not the growth of trees.

Explanation:

8 0
2 years ago
What is the value of Kw at 25°C?<br> 1.0 x 10–14 <br> 1.0 x 10–7<br> 1<br> 7<br> 14
romanna [79]
<span>1.0 x 10-14. That is the value of Kw at 25 degrees C.


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3 0
3 years ago
Read 2 more answers
Chlorine is the most widely used disinfectant for killing pathogens during water treatment. Determine the kilograms of chlorine
makkiz [27]

Explanation:

The given data is as follows.

    Flow of chlorine (Q) = 10,000 m^{3}/day

Amount of liter present per day is as follows.

                  10,000 \times 10^{3} l/day

It is given that dosage of chlorine will be as follows.

                   10 mg/l = 10 \times 10^{-6} kg/l

Therefore, total chlorine requirement is as follows.

          Total chlorine requirement = (10,000 \times 10^{3}) \times (10 \times 10^{-6}) kg/day

                                        = 100 kg/day

Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.

4 0
3 years ago
How are half life and radioactive decay related
hoa [83]

Answer : Half life and radioactive decay are inversely proportional to each other.

Explanation :

The mathematic relationship between the half-life and radioactive decay :

N=N_oe^{-\lambda t}              ................(1)

where,

N = number of radioactive atoms at time, t

N_o = number of radioactive atoms at the beginning when time is zero

e = Euler's constant = 2.17828

t = time

\lambda = decay rate

when t=t_{1/2} then the number of radioactive decay become half of the initial decay atom i.e N=\frac{N_o}{2}.

Now substituting these conditions in above equation (1), we get

\frac{N_o}{2}=N_oe^{-\lambda t_{1/2}}

By rearranging the terms, we get

\frac{1}{2}=e^{-\lambda t_{1/2}}

Now taking natural log on both side,

ln(\frac{1}{2})=-\lambda \times t_{1/2}

By rearranging the terms, we get

t_{1/2}=\frac{0.693}{\lambda}

This is the relationship between the half-life and radioactive decay.

Hence, from this we conclude that the Half life and radioactive decay are inversely proportional to each other. That means faster the decay, shorter the half-life.

3 0
3 years ago
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