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3 years ago

The requirements of atoms to be able to participate in hydrogen bonding with a hydrogen atom include

Chemistry

2 answers:

vladimir1956 [14]3 years ago

4 0

C the atoms size is irrelevant

leva [86]3 years ago

3 0

Answer: C. atoms must be small.

Explanation: Hydrogen bond is the result of the electrostatic forces of attraction between the hydrogen and the electonegative atom. It is a type of dipole dipole interaction which is not so much of a covalent bond.

The options A, B and D satisfies the definition of the hydrogen bonding but the option C seems to be irrelevant as hydrogen bonding does not deal with the size of the atom.

Thus for the hydrogen bonding , the other atom must be electronegative, and atoms must have atleast one lone pair of electrons and atoms must not be able to closely approach the hydrogen.

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Andi performs the calculation that is shown below.

rodikova [14]

Answer: 3.59

Explanation:

(2.06)(1.743)(1.00)

2.06 × 1.743 × 1.00

= 3.59058

Two of the multiplied digits are represented in 3 significant figures. Therefore, for correct representation, the result of the product should be written to three significant figures.

3.59058 to 3 significant figures:

First three digits = 3.59

Fourth digit '0' is less than 5, and thus rounded to 0 with other succeeding digits

Therefore, (2.06)(1.743)(1.00) to 3 significant figures equals :

3.59

3 0

3 years ago

Please help it’s due asap<br> I WILL GIVE BRAINLIEST

inna [77]

I think it’s number 5 and number 9 hopes this helps.

4 0

3 years ago

How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----> K3PO4 + 3

8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

$\frac{3}{1} =\frac{y}{0.02256} \\$

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0

3 years ago

Please help. Im not a very smart person

GenaCL600 [577]

Either it’s, it is released when the reaction is complete or it is changed into atoms of carbon and oxygen during the reaction

7 0

2 years ago

Do you know any of the answers

zzz [600]

Answer:

soorry i ddsmfcj know

Explanation:

4 0

3 years ago