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RUDIKE [14]
2 years ago
9

The fuel used to power the booster rockets on space shuttles is a mixture of aluminum metal and ammonium perchlorate. the follow

ing balanced equation represents the reaction.. 3al 3nh4clo4 → al2o3 alcl3 3no 6h2o how many moles of water are produced from 373 mol al?
Chemistry
1 answer:
Charra [1.4K]2 years ago
6 0

The moles of water that are produced from 373 moles of ammonia present in any chemical reaction is 746 moles.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the amount of entities present in any chemical reaction before and after the reaction.

Given chemical reaction is:

3Al + 3NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3NO + 6H₂O

From the stoichiometry of the reaction it is clear that:

3 moles of Al = produces 6 moles of H₂O

373 moles of Al = produces 6/3×373 = 746 moles of H₂O

Hence required moles of water is 746 moles.

To know more about stoichiometry, visit the below link:

brainly.com/question/21931988

                                                                                                                                                                                                                                                                                                                               

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A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
If 20 grams of N2 react completely with H2 , how many moles of NH3 are produced? Show Work
Maslowich
This is the balanced eq
N2 + 3H2 -> 2NH3
first you need to find mole of N2 by using
mol = mass ÷ molar mass.
mol N2= 20g ÷ (14.01×2)g/mol
=0.7138mol
then look at the coefficient between H2 and NH3.
it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
moles of NH3 = 1.4276 moles
5 0
3 years ago
A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a
svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0
3 years ago
If you have a 4.0 g of radioactive substance left after 4 half-lives have passed then how much did you have originally?
kirza4 [7]

4.0 +4.0= 8.0

8.0+8.0=16.0

16.0+16.0=32.0

32.0+32.0=64.0

6 0
3 years ago
If the caterpillar keeps moving at the same speed, how long will it take to travel 6cm?
Solnce55 [7]

It will take 15 s to travel 6 cm

<h3>Further explanation</h3>

Given

distance versus time graph

Required

time travel

Solution

Caterpillar motion is a straight motion with a constant speed, so that the graph between distance and time forms a diagonal line

If we look at the graph, we can determine the time taken when the distance reaches 6 cm (y axis) by drawing a line to the diagonal line and cutting the x-axis as time, and we get 15 s

Or we can also use the formula for motion at constant speed:

d = v x t

With v at point 2,5 of 2/5 m / s, so the time taken:

\tt t=\dfrac{d}{v}=\dfrac{6}{2/5}=15~s

4 0
3 years ago
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