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3 years ago

How many places are there for electrons in the third shell of an atom?

1 answer:

7 0

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.

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Write equations for the initiation and propagation steps for the formation of dichloromethane by free radical

olya-2409 [2.1K]

Name of type of mechanism initiation step first propagation step second propagation step(ii) write an overall equation for the formation of dichloromethane from ... Best Answer: i) This is a free-radical substitution mechanism.

7 0

2 years ago

Lead (II) nitrate reacts with ammonium carbonate to produce ammonium nitrate

vitfil [10]

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

Explanation:

Reaction of lead (II) nitrate with ammonium carbonate will produce lead (II) carbonate and ammonium nitrate.

The balanced chemical equation is:

Pb(NO₃)₂ + (NH₄)₂CO₃ → PbCO₃ + 2 NH₄NO₃

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Learn more about:

balancing chemical reactions

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3 0

3 years ago

What will happen when a tree fell in a river

beks73 [17]

It's depending on what size of the tree it is. For example, if the tree is large it will block most of the water that runs through. If the tree is small it shouldn't do as much besides block a little amount of water and it will probably go down stream.
This is based on my thinking

8 0

3 years ago

Read 2 more answers

If you had a 0.800 L solution containing 0.0240 M of Fe3+(aq), and you wished to add enough 1.38 M NaOH(aq) to precipitate all o

guapka [62]

Answer:

0.041 L = 41.3 mL

Explanation:

This problem we will solve by considering the stoichiometry of the reaction and the definition of molarity.

Number of moles in .800 L solution:

0.800 L x 0.0240 M = 0.800 L x .0240 mol/L = 0.0192 mol Fe³⁺

to form the precipitate Fe(OH)₃ we will need 3 times .0192

mol NaOH required = 0.057

given the concentration of 1.38 mol M NaOH we can calculate how many milliliters of NaOH will contain 0.057 mol:

1.L/1.38 mol NaOH x 0.057 mol NaOH = 0.041 L

0.041 L x 1000 mL/1L = 41.3 mL

7 0

3 years ago

Your lab partner combined chloroform and acetone to create a solution where the mole fraction of chloroform, Xchloroform, is 0.1

jeyben [28]

Answer:

Explanation:

[u]Assumptions[/u]

1. There is exactly 1 mole of chloroform

2. The liquids mix together well such that the volume of the solution is the sum of the volumes of the two liquids

Given that the mole fraction of the Chloroform is 0.171

Mole fraction of Chloroform =

Mole of chloroform /(Mole of chloroform + mole of acetone)

According to assumptions, mole of chloroform is equal to 1

Therefore 0.171 =1/(1+mole of acetone)

1 + mole of acetone = 1/0.171

Mole of acetone = 1(/0.171) - 1

Moles of acetone = 4.85mol.

From Stochiometry

Mass of acetone = Mole of acetone * Molar Mass of acetone

Molar mass of acetone = 58.1grams/mol

Mass of acetone = 4.85 *58.1 = 282g =0.282kg

Mass of chloroform = moles of chloroform *Molar mass of Chloroform

Molar mass of chloform = 119.4 grams/mol

Mass of chloroform = 1* 119.4 =119.4g=0.1994kg

Volume of acetone = Mass of acetone / Density of acetone

Volume of acetone = 282/0.791

Volume of acetone = 357mL

Volume of Chloroform = Mass of Chloroform /Density of Chloroform

Volume of Chloroform = 119.4/1.48

= 81mL

Total volume of solution = 357mL+81mL = 438mL = 0.438L

1. Molarity = Moles of solute(chloroform)/mass of solvent (acetone) in kg

Molarity = 1/0.282 = 3.55molal

2. Molarity = moles of solute( chloroform) /Volume of solution

= 1/0.438 =2.28Molar

Therefore the molality and molarity respectively are 3.55 and 2.28.

4 0

3 years ago