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2 years ago

Al2(CO3)3

Chemistry

1 answer:

Alborosie2 years ago

3 0

Answer:

7. 6 atoms po

Explanation:

sana makatulong po

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A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th

mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene, Solvent 2 = water

$K_{p}$ = 2.7, $V_{S_{2}}$ = 100 mL

$V_{S_{1}}$ = 10 mL, weight of compound = 1 g

Extract = 3

Therefore, calculate the fraction remaining as follows.

$f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}$

= $[1 + 2.7(\frac{100}{10})]^{-3}$

= $(28)^{-3}$

= $4.55 \times 10^{-5}$

Hence, weight of compound to be extracted = weight of compound - fraction remaining

= 1 - $4.55 \times 10^{-5}$

= 0.00001

or, = $1 \times 10^{-5}$

Thus, we can conclude that weight of compound that could be extracted is $1 \times 10^{-5}$ .

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2 years ago

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After reading a book about parrots, Tani wants to learn more about them. Which question could be answered through scientific inv

FrozenT [24]

After reading a book about parrots, Tani wants to learn more about them. The question that could be answered through scientific investigation is letter B, ‘What substances make up an eggshell?’ The other choices cannot be answered through scientific investigation.

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answer last one “How many moles of hydrogen are consumed to produce 100 g ammonia” ? explanation and answer required then u get

SVETLANKA909090 [29]

Answer:

The answer is 17.03052. We assume you are converting between grams Ammonia and mole.

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2 years ago

Which shows the weight of an atom?

sammy [17]

Answer:

The atomic mass

Explanation:

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2 years ago

An element consists of two isotopes. One with a mass of 79.95 amu and an abundance of 29.9%. The second isotope has a mass of 81

galina1969 [7]

the molar mass of the element is 81.36 g/mol

calculation

step 1 : multiply each %abundance of the isotope by its mass number

that is 79.95 x 29.9 =2391

81.95 x 70.1 = 5745

Step 2: add them together

2390.5 + 5744.7 =8136

Step 3: divide by 100

= 8136/100 = 81.36 g/mol

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2 years ago