Answer: n∗R=22+273.15/4.2∗5n
P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10
Explanation:
Answer:
did you mean moles? If so, answer is down below.
Explanation:
there are 0.106 moles of glucose in 19.1 g of glucose.
Answer : The retention time is, 20 min
Explanation :
Retention time : It is defined as the amount of time a compound spends on the column after it has been injected.
Formula of retention time is:
Given:
Distance from injection point to center of peaks = 10 cm
Chart recorded speed = 0.5 cm/min
Now put all the given values in the above formula, we get:
Retention time = 20 min
Thus, the retention time is, 20 min
Answer:
72.6 mL
Explanation:
A quick way to solve this titration problem when you have a monoprotic acid is to use the Dilution equation, M1V1=M2V2.
.589(x)=.821(52.1)
X=72.6 mL
The answer
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH - is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =<span>0.001 62
and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -]
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79
finally pH = 14 -2.79 = 11.20
