Answer:
1.47 Liters of O₂ were reacted
Explanation:
The reaction is:
2H₂ (g) + O₂(g) → 2H₂O(l)
As we have the volume of hydrogen we need to work with denstiy to determine the moles that have reacted.
Density = mass / volume
Density . volume = mass → 0.071 g/L . 3.74L = 0.265 g
We determine the moles of H₂ → 0.265 g. 1mol/2g = 0.132 moles
In the reaction, ratio is 2:1. We make a rule of three:
2 moles of H₂ need 1 mol of O₂ to react
Then, 0.132 moles would need (0.132 .1)/2 = 0.066 moles of O₂
In order to determine the volume we need the oxygen's density but, we have to convert the mass to moles, firstly.
0.066 moles . 32 g/ 1mol = 2.12 g
Then oxygen's density = oxygen's mass / oxygen's volume
Oxygen's volume = oxygen's mass / oxygen's density
O₂ volume = 2.12 g / 1.43 g/L = 1.47 L
