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Likurg_2 [28]
3 years ago
12

Plz helppppppppppppppp

Chemistry
1 answer:
kipiarov [429]3 years ago
5 0

Density does not change with the amount of matter.

The density of water is 1 g/mL whether you have 1 mL or 1000 mL of water. Density is an i<em>ntensive </em>property.

Mass, volume, and weight change with the quantity of matter. For example, the mass of 1000 mL of water is greater than the mass of 1 mL of water. Mass, volume, and weight are <em>extensiv</em>e properties.


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Carbon dioxide and ____ are outputs of cellular respiration
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Which statement about the relationship between laws, hypotheses, and theories is true?
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A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate
AlladinOne [14]

The given question is incomplete. The complete question is as follows.

A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and then found to have a mass of 212 mg. What mass of barium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction.)

Explanation:

When Ba^{2+} and Na_{2}SO_{4} are added  then white precipitate forms. And, reaction equation for this is as follows.

       Ba^{2+} + SO^{2-}_{4} \rightarrow BaSO_{4}

It is given that mass (m) is 212 mg or 0.212 g (as 1 g = 1000 mg). Molecular weight of BaSO_{4} is 233.43.

Now, we will calculate the number of moles as follows.

  No. of moles = mass × M.W

                        = \frac{0.212}{233.43}

                        = 0.00091 mol of BaSO_{4}

Hence, it means that 0.00091 mol of Ba^{2+}. Now, we will calculate the mass as follows.

       Mass = moles × MW

                 = 0.00091 \times 137.327

                 = 0.124 grams or 124 mg of barium

Thus, we can conclude that mass of barium into the original solution is 124 mg.

8 0
3 years ago
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